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ValentinkaMS [17]
2 years ago
9

Iodine is blue-black, crystalline, and solid. It sublimes to a violet-colored gas and reacts with aluminum and many other metals

. Which of these five properties are physical? (Select all that apply.) blue-black crystalline solid sublimes to a violet-colored gas reacts with aluminum and many other metals Which are chemical? (Select all that apply.) blue-black crystalline solid sublimes to a violet-colored gas reacts with aluminum and many other metals
Chemistry
1 answer:
Pepsi [2]2 years ago
4 0

Answer:

  • blue-black PHYSICAL PROPERTY
  • crystalline PHYSICAL PROPERTY
  • solid PHYSICAL PROPERTY
  • sublimes to a violet-colored gas PHYSICAL PROPERTY
  • reacts with aluminum and many other metals CHEMICAL PROPERTY

Explanation:

Chemical properties are visible through chemical reactions, in which the chemical identity changes to form new substances. On the other hand, physical properties are evident without a change in the identity of a substance.

<em />

<em>Which of these five properties are physical and which are chemical?</em>

  • blue-black PHYSICAL PROPERTY
  • crystalline PHYSICAL PROPERTY
  • solid PHYSICAL PROPERTY
  • sublimes to a violet-colored gas PHYSICAL PROPERTY
  • reacts with aluminum and many other metals CHEMICAL PROPERTY
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Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymer
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Answer:

C₃H₄O₂ → 50% C; 5.5 % H; 44.5% O

C₄H₆O₂ → 56 % of C; 7 % of H; 37% of O

C₃H₃N → 68 % of C; 6 % of H; 26 % of N

Explanation:

We determine the molar mass of each compound:

C₃H₄O₂ → 72 g/mol

In 1 mol of acrylic acid (72 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

4 moles of H → 1 g/mol . 4 mol = 4 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 36 / 72 = 50 % of C

4 . 100 / 72 = 5.5 % of H

32 . 100 / 72 = 44.5 % of O

C₄H₆O₂ → 86 g/mol

In 1 mol of methyl acrylate (86 g), we have:

4 moles of C → 12 g/mol . 4 mol = 48 g of C

6 moles of H → 1 g/mol . 6 mol = 6 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 48 / 86 = 56 % of C

6 . 100 / 86 = 7 % of H

32 . 100 / 86 = 37 % of O

C₃H₃N → 53 g/mol

In 1 mol of acrylonitrile (53 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

3 moles of H → 1 g/mol . 3 mol = 3 g of H

1 mol of N → 14g/mol . 1 mol = 14 g of N

Then in 100 g of salt, we may have:

100 . 36 / 53 = 68 % of C

3 . 100 / 53 = 6 % of H

14 . 100 / 53 = 26 % of N

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Explanation:

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2 years ago
1.2 L sample of gas is determined to contain 0.5 moles of nitrogen. At the same temperature and pressure, how many moles of gas
hram777 [196]

A 20 L sample of the gas contains 8.3 mol N₂.

According to <em>Avogadro’s Law,</em> if <em>p</em> and <em>T</em> are constant

<em>V</em>₂/<em>V</em>₁ = <em>n</em>₂/<em>n</em>₁

<em>n</em>₂ = <em>n</em>₁ × <em>V</em>₂/<em>V</em>₁

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<em>n</em>₁ = 0.5 mol; <em>V</em>₁ = 1.2 L

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∴<em>n</em>₂ = 0.5 mol × (20 L/1.2 L) = 8.3 mol

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3 years ago
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