Answer:
Wind is the horizontal movement of air, transporting energy transferred from the earth's surface as sensible and latent heat. Sensible heat is transferred by the processes of conduction and convection. Conduction transfers energy within a substance, and convection transfers energy through the vertical movement of the heated substance. Latent heat is the transfer of energy by transforming the substance itself. As you recall, water has the ability to exist as liquid, gas or solid. The transformation from liquid to gas is called evaporation; the reverse process, from gas to liquid, is called condensation; from liquid to solid is known as solidification (freezing); and from solid to liquid, fusion (melting). Water can also be transformed directly from solid to gas (sublimation), or the reverse, through a process called deposition. We will see these various processes in the formation of clouds.
Explanation:
if I did not give answer then i hope i at least helped!
Answer:
VH2SO4 = 145.3 mL
Explanation:
Mw BaO2 = 169.33 g/mol
⇒ mol BaO2 = 53.5g * ( mol BaO2 / 169.33 g BaO2) = 0.545 mol BaO2
⇒according to the reaction:
mol BaO2 = mol H2SO4 = 0.545 mol
⇒ V H2SO4 = 0.545 mol H2SO4 * ( L H2SO4 / 3.75 mol H2SO4 )
⇒V H2SO4 = 0.1453 L (145.3 mL)
Answer:
4.7 atm
Explanation:
From the question given above, the following data were obtained:
Total pressure (P) = 15.3 atm
Pressure of Helium, P(He) = 3.2 atm
Pressure of Oxygen, P(O) = 7.4 atm
Pressure of Argon, P(Ar) =?
The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:
P = P(He) + P(O) + P(Ar)
15.3 = 3.2 + 7.4 + P(Ar)
15.3 = 10.6 + P(Ar)
Collect like terms
15.3 – 10.6 = P(Ar)
4.7 = P(Ar)
P(Ar) = 4.7 atm
Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm
It’s the second won the air layer one
By law of conservation of energy, the amount of heat lost
by the metal should be equal to the amount of heat gained by water. That is,
the change in energy (expressed in enthalpies) should be equal:
- (ΔH)metal = (ΔH)water
Take note of the negative sign in front of (ΔH)metal, this
means that heat is lost by this metal.
Where ΔH or change in enthalpy is:
ΔH = m Cp (T2 – T1)
So,
- 15 g (Cp) (23 °C – 99 °C) = 75 g (4.18 J/g * °C) (26 °C –
23 °C)
1,140 Cp = 940.5
<span>Cp = 0.825 J/g * °C (ANSWER)</span>
