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3 years ago

What is the solution to this system of equations?

1 answer:

4 0

2t = 40 - 2w
t = 40/2 (-2/2)w
t = 20 - w -- rearrange
t = -w + 20

t + w = 15
t = -w + 15

same slope, different y intercepts.....parallel lines, no solutions

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Answer:

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2 years ago

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Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

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Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

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Bas_tet [7]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers