Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
Answer:
a = 4 + -1.333333333b
Step-by-step explanation:
Simplifying
3a + 4b = 12
Solving
3a + 4b = 12
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-4b' to each side of the equation.
3a + 4b + -4b = 12 + -4b
Combine like terms: 4b + -4b = 0
3a + 0 = 12 + -4b
3a = 12 + -4b
Divide each side by '3'.
a = 4 + -1.333333333b
Simplifying
a = 4 + -1.333333333b
Answer:
A = 236,000 (1.04)^t
population in 2009 : 335,902 people
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form) = 4/100 = 0.04
t= years passed from 2000
A = population after t years
Replacing with the values given:
A = 236,000 (1+ 0.04)^t
A = 236,000 (1.04)^t
Population in 2009.
t = 2009-2000 = 9
A = 236,000 (1.04)^9
A = 335,902 people
Feel free to ask for more if needed or if you did not understand something.
