Question

Write an explicit formula for the recursive formula shown below: A(n)=A(n-1)+3; A(1)=6

Answer 1

Answer:

$a_n=A(n)=3n+3.$

Step-by-step explanation:

You are given recursive formula $A(n)=A(n-1)+3,$ where $A(1)=6.$

Find some terms of the sequence:

$a_1=A(1)=6,\\ \\a_2=A(2)=A(1)+3=6+3=9,\\ \\a_3=A(3)=A(2)+3=9+3=12,\\ \\a_4=A(4)=A(3)+3=12+3=15,...$

You van see that these terms form the arithmetic sequence with first term $a_1=6$ and difference $d=3.$

An explicit formula for n-th term of arithmetic sequence is

$a_n=a_1+(n-1)d.$

In your case,

$a_n=6+(n-1)\cdot 3,\\ \\a_n=6+3n-3,\\ \\a_n=3n+3.$