In order to rationalize the denominator of each expression, we need to multiply the expression by the same radical in the denominator, this way we can remove the radical from the denominator.

$\frac{5\sqrt{4}}{\sqrt{3}}(\cdot\sqrt{3})=\frac{5\sqrt{4}\sqrt{3}}{(\sqrt{3})^2}=\frac{5\cdot2\cdot\sqrt{3}}{3}=\frac{10\sqrt{3}}{3}$

10)

$-\frac{5}{3\sqrt{2}}(\cdot\sqrt{2})=-\frac{5\sqrt{2}}{3(\sqrt{2})^2}=-\frac{5\sqrt{2}}{3\cdot2}=-\frac{5\sqrt{2}}{6}$

11)

$\frac{2\sqrt{3}}{4\sqrt{5}}(\cdot\sqrt{5})=\frac{2\sqrt{3}\sqrt{5}}{4(\sqrt{5})^2}=\frac{2\sqrt{15}}{4\cdot5}=\frac{\sqrt{15}}{2\cdot5}=\frac{\sqrt{15}}{10}$

12)

$\frac{\sqrt{5}}{\sqrt{2}}(\cdot\sqrt{2})=\frac{\sqrt{5}\sqrt{2}}{(\sqrt{2})^2}=\frac{\sqrt{10}}{2}$

3 0

11 months ago

Find the equation, in point-slope form, of the line that passes -3 and passes through the point (1,2). plz show your work.

Maslowich

Substitute the given values for the parameters in the point-slope form of the equation of a line. That form is
y - k = m(x - h)
for point (h, k) and slope m.

You have (h, k) = (1, 2) and m=-3, so your equation is
y - 2 = -3(x - 1)

4 0

3 years ago

Today only, a table is being sold for $333 . This is 74% of its regular price. What was the price yesterday?

Vinil7 [7]

The table was being sold at $450 yesterday

5 0

2 years ago