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Nostrana [21]
2 years ago
8

Needing Help!!! Please Answer Fast! :)

Mathematics
2 answers:
zimovet [89]2 years ago
8 0
Pls help me I stuck and I’m only a 4 grader
NeTakaya2 years ago
6 0

Answer:

C

Step-by-step explanation:

Use the vertical line text. If any vertical line intersect the relation at more than one point, it is not a function. So, using this method, you get C.

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What is the solution set of the equation?<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20-18%2B9x%3Dx" id="TexFormula1"
bagirrra123 [75]

9514 1404 393

Answer:

  x ∈ {2.07014981016}

Step-by-step explanation:

The equation can be rewritten as ...

  √x = 18-8x

  x = 324 -288x +64x²

  64x² -289x +324 = 0

  x = (289 ±√577)/128 ≈ {2.07015, 2.44548}

Since √x must be positive, we know that ...

  18 -8x ≥ 0

  x ≤ 18/8 = 2.25

The larger of the above solutions is extraneous, so the solution set is ...

  x ∈ {(289 -√577)/128} ≈ {2.07015}

8 0
2 years ago
Complete the missing value in the solution to the equation:<br> 8x + x - y = 2x + 12 + 2y<br> ( ,3
Digiron [165]
The answer to the missing value is X = 3

6 0
2 years ago
What’s the correct answer for this?
andreev551 [17]

Answer:

the first one

Step-by-step explanation:

hope this helps

6 0
3 years ago
Read 2 more answers
6 + (9 − 1) 2 ÷ 4 ⋅ 1 over 2 whole to the power of 4
Bas_tet [7]

Answer:

625

Step-by-step explanation:

1. parenthesis first, so it simplifies to ((6+(8)2÷4*1)/2)^4

2. pemdas says that multiplication and division go before addition and subtraction, so ((6+(8)2÷4*1)/2)^4 becomes ((6+16÷4*1)/2)^4 ---> ((6+4)/2)^4

3. then simplify inside of the parenthesis, so it becomes 5^4, which is 625

6 0
2 years ago
If sin 0 = 15/17 use pythagorean identity to find cos 0
Inga [223]
Hello : 
sin<span>θ = 15/17
</span> use pythagorean identity : cos²θ +sin² θ = 1 
cos²θ =  1 - sin² θ
cos²θ = 1-(15/17)² 
cos²θ = 1- 225/289
cos²θ = 64/289
cos²θ = (8/17)²
cosθ = 8/17 or -8/17
8 0
2 years ago
Read 2 more answers
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