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3 years ago

What percent of 2358 is 90? Step by step please

Mathematics

2 answers:

hoa [83]3 years ago

7 0

Answer:

3.8%

Step-by-step explanation:

90/2358=0.038

Vladimir [108]3 years ago

7 0

Step-by-step explanation: To answer the question what percent of 2,358 is 90, we translate the question into an equation.

"What percent" means x, "of 2,358" means times 25, and "is 90" means equals 90.

Now to solve for x, since x is being multiplied by 2,358, we need to divide by 2,358 on both sides of the equation.

On the left side of the equation the 2,358's cancel and we have x. On the right side of the equation we have 90 divided by 2,358 which is 0.03816.

Now, remember we want to write our answer as a percent so to write 0.03816 as a percent, we move the decimal point two places to the right and we have 3.8160%.

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8. Sheila buys two concert tickets from her friend.

dalvyx [7]

Cost of two tickets that Sheila paid to her friend = $ 90

Actual price of 1 ticket = $ 52.50

So, actual price of 2 tickets = 52 x 2 = 105

Hence, markdown or discount Sheila's friend gave her is =

105 - 90 = 15

The answer is $15.

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2 years ago

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Given: angle 1 is supplementary to angle 2 and angle 1 is congruent to angle 3.

gregori [183]

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3 years ago

$10,000 is compounded semiannually at 12% interest for t years. what expression represents the amount of money after t years?

kari74 [83]

To solve this, you can do the is over of equals to % over hundred.
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3 0

3 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago

8,11,14,17 and you have to find the 74th term

astra-53 [7]

Answer:

227 is the 74th term of your question.

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2 years ago