Answer:
Step-by-step explanation:
move all the terms to the right so your equation will equal 0. then look for the common denominator. which in this case is 60 (5*4*3).
multiply all terms by 60 then simplify.
12(2x-3)-15(6-3x)+120-20(7x)=0
24x-36-90+45x+120-140x=0
combine like terms and then divide
-71x=6
x=-6/71
(do not forget parenthesis when simplifying they are very important when it comes to distributing the minus sign)
The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
Two cups in a pint,at least here in the us
Answer:
When the eqn cuts the x-axis , y=0
3x=12
x=12/3
x=4
So,at x=4 is the point at which the linear equation cuts the x-axis
The value of y should be 8
