To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=12 and j+k=b=8, so j and k must be 2 and 6
Then the factors are just (a+j)(a+k), in this case:
(a+2)(a+6)
So the missing term was 6
The 1st one is the right answer
(-4,0) (3,-5) I don't know if they mean two ordered pairs so I'm pretty sure this is right
I will go about solving this using the elimination method.
First, convert the equations.
10x + y = -20
4x + y = -12
Second, find the easiest variable to get rid of and get rid of it! (In this case, y) We will subtract to get rid of y.
6x = -8
Third, you want to solve the equation.
6x = -8 (divide by 6)
x =

Fourth, solve for y by inserting the answer for x into one of the equations.
10(

) + y = -20

+ y = -20 (subtract

)
y =

The solution for this system of equations is (

,

).
Answer:
Harry = 10 toys
Mark = 20 toys
Sue = 20 toys
Step-by-step explanation:
H + M + S = 50
H = M - 10
S = 2H
Harry = 10 toys
Mark = 20 toys
Sue = 20 toys