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Vladimir79 [104]

2 years ago

12

4x+3x^2-8x+5x^2 I need help quick !!!

2 answers:

suter [353]2 years ago

7 0

Answer:

8x^2 - 4x

Step-by-step explanation:

add like terms

stepan [7]2 years ago

5 0

Collect like terms and simplify.

$4x+3x^2-8x+5x^2 \\\\(4x-8x)+(3x^2+5x^2)\\\\-4x+8x^2$

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The number 46 comma 462 comma 555 46,462,555 rounded to the nearest million is

Nataliya [291]

The nearest million is 46 million since if the number to the right of "nearest so and so" is less than 5, you round down but if it is 5 or more then you round up.
Hope this helps!

8 0

3 years ago

A movie theater is open x hours Monday through Thursday and y hours Friday through Sunday. Write an algebraic expression that re

Georgia [21]

Answer: x+y

Step-by-step explanation:

Simple.

Since there is nothing splitting, all you need to do is add x and y.

To break it down:

They want to know the hours per week the theater is open. X represents the hours from Sunday to Thursday and Y represents hours from Friday to Sunday therefor all you need to do is add them because they represent Hours.

5 0

2 years ago

Read 2 more answers

[tex]cos {}^{4} α+sin {}^{4} α= \frac{1}{4} (3+cos4α)<br>Prove:<br>

asambeis [7]

Given:

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

To prove:

The given statement.

Proof:

We have,

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

$LHS=\cos^4 \alpha+\sin^4\alpha$

$LHS=(\cos^2 \alpha)^2+(\sin^2 \alpha)^2$

$LHS=(\cos^2 \alpha+\sin^2\alpha)^2-2\sin ^2\alpha\cos^2 \alpha$ $[\because a^2+b^2=(a+b)^2-2ab]$

$LHS=(1)^2-2(1-\cos^2 \alpha)\cos^2 \alpha$ $[\because \cos^2 \alpha+\sin^2\alpha=1]$

$LHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

Now,

$RHS=\dfrac{1}{4}(3+\cos 4 \alpha)$

$RHS=\dfrac{1}{4}[3+(2\cos^2 2\alpha-1)]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2\cos^2 2\alpha]$

$RHS=\dfrac{1}{4}[2+2(2\cos^2 \alpha-1)^2]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2(4\cos^4 \alpha-4\cos \alpha+1)]$ $[\because (a-b)^2=a^2-2ab+b^2]$

$RHS=\dfrac{1}{4}[2+8\cos^4 \alpha-8\cos \alpha+2]$

$RHS=\dfrac{1}{4}[4+8\cos^4 \alpha-8\cos \alpha]$

$RHS=1+2\cos^4 \alpha-2\cos \alpha$

$RHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

$LHS=RHS$

Hence proved.

8 0

3 years ago

Is a prime number is a number times itself yes it is

Sladkaya [172]

Answer:

yup

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

For each set of values find x - y. Answer the questions that follow. <br> X=14, y=-2

gtnhenbr [62]

16 because the neg next to the subtraction sign becomes positive then you’re just adding 14+2.

4 0

2 years ago