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vovangra [49]
3 years ago
12

chemist heats 100.0 g of in a crucible to drive off the water. If all the water is driven off, what is the mass of the remaining

salt?
Chemistry
2 answers:
serious [3.7K]3 years ago
8 0

Answer:

54.6

Explanation:

on edg 2020

Nataliya [291]3 years ago
8 0

Answer:

54.6 is correct

Explanation:

...

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(Please explain the answer. Thank you!)
Dominik [7]

Sample cost = $15.796

<h3>Further explanation</h3>

Given

Mass = 2 g

Density = 0.718 g/ml

Cost =  $5.67 per mL

Required

Cost

Solution

The density : the ratio of mass and volume

Can be formulated :

Density (ρ) = m : V

The volume of the liquid :

V = m : ρ

V = 2 g : 0.718 g/ml

V = 2.786 ml

Sample cost :

= 2.786 ml x $5.67/ml

= $15.796

7 0
3 years ago
How can both the pitcher and the glass contain the same volume of iced tea? ​
Kipish [7]

Answer:

Because of their spaceeeee isss different

8 0
3 years ago
Is 4Si2H3 + 11O2=8SiO2+6H2O balanced
k0ka [10]

Answer:

Yes it is indeed balanced, and balanced correctly at that.

Explanation:

5 0
4 years ago
A cold can of soda is taken out of the refrigerator. It slowly warms up until it is at room temperature. Once the soda has warms
lara31 [8.8K]

Answer:

See explanation

Explanation:

We know that the thermal energy of a substance largely depends on the temperature of the body. This implies that the hotter a substance is, the greater its thermal energy and vice versa.

When you bring a cold can of soda out of the refrigerator, the molecules of air at room temperature gradually loose energy to the can and condense around it. This transfers thermal energy from the air particles to the molecules in the cold can of soda and the soda warms up pretty soon!

5 0
3 years ago
Suppose you have just added 100 ml of a solution containing 0.5 mol of acetic acid per liter to 400 ml of 0.5 m naoh. what is th
Tpy6a [65]

pH = 13.5

Explanation:

Sodium hydroxide completely ionizes in water to produce sodium ions and hydroxide ions. Hydroxide ions are in excess and neutralize all acetic acid added by the following ionic equation:

\text{HAc} + \text{OH}^{-} \to \text{Ac}^{-} + \text{H}_2\text{O}

The mixture would contain

  • 0.4 \times 0.5 - 0.1 \times 0.5 = 0.15 \; \text{mol} of \text{OH}^{-} and
  • 0.1 \times 0.5 = 0.05 \; \text{mol} of \text{Ac}^{-}

if \text{Ac}^{-} undergoes no hydrolysis; the solution is of volume 0.1 + 0.4 = 0.5 \; \text{L} after the mixing. The two species would thus be of concentration 0.30 \; \text{mol} \cdot \text{L}^{-1} and 0.10 \; \text{mol} \cdot \text{L}^{-1}, respectively.

Construct a RICE table for the hydrolysis of \text{Ac}^{-} under a basic aqueous environment (with a negligible hydronium concentration.)

\begin{array}{cccccccc} \text{R} & \text{Ac}^{-}(aq) &+ & \text{H}_2\text{O}(aq) & \leftrightharpoons & \text{HAc}(aq) & + & \text{OH}^{-} (aq)\\ \text{I} & 0.10 \; \text{M} & & & & & &0.30 \; \text{M}\\ \text{C} & -x \; \text{M}& & & & +x \; \text{M}& & +x \; \text{M} \\ \text{E} & (0.10 - x) \; \text{M} & & & & x \; \text{M} & & (0.30 +x) \; \text{M} \end{array}

The question supplied the <em>acid</em> dissociation constant pK_afor acetic acid \text{HAc}; however, calculating the hydrolysis equilibrium taking place in this basic mixture requires the <em>base</em> dissociation constant pK_b for its conjugate base, \text{Ac}^{-}. The following relationship relates the two quantities:

pK_{b} (\text{Ac}^{-}) = pK_{w} - pK_{a}( \text{HAc})

... where the water self-ionization constant pK_w \approx 14 under standard conditions. Thus pK_{b} (\text{Ac}^{-}) = 14 - 4.7 = 9.3. By the definition of pK_b:

[\text{HAc} (aq)] \cdot [\text{OH}^{-} (aq)] / [\text{Ac}^{-} (aq) ] = K_b =  10^{-pK_{b}}

x \cdot (0.3 + x) / (0.1 - x) = 10^{-9.3}

x = 1.67 \times 10^{-10} \; \text{M} \approx 0 \; \text{M}

[\text{OH}^{-}] = 0.30 +x \approx 0.30 \; \text{M}

pH = pK_{w} - pOH = 14 + \text{log}_{10}[\text{OH}^{-}] = 14 + \text{log}_{10}{0.30} = 13.5

6 0
3 years ago
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