Is 4Si2H3 + 11O2=8SiO2+6H2O balanced

Please help! 20 Points!!!

lorasvet [3.4K]

Answer:

I just did it home slice the first one's Ag+ and Zn2+ and the second one is A

Explanation:

I just did the assignment

7 0

2 years ago

Read 2 more answers

the following reaction gives a product with the molecular formula c4h8o2. draw the structure of the product.

grandymaker [24]

The following reaction gives a product with the molecular formula C₄H₈O₂. The diagram of the structure of the product can be seen in the image attached below.

The reaction between C₂H₂(ONa)₂ and C₂H₄Br results in the formation of the product C₄H₈O₂ and 2NaBr.

This reaction undergoes an SN₂ mechanism since there is no stable carbocation formed. In the reaction -O⁻Na⁺ attacks the ortho position in C₂H₄Br to form C₄H₈O₂.

In SN₂ mechanism is a nucleophilic substitution reaction where one bond is formed while another one is broken simultaneously.

The mechanism for the reaction can be seen in the image attached below.

Learn more about nucleophilic substitution reaction here:

brainly.com/question/4699407?referrer=searchResults

7 0

3 years ago

How do you solve this problem

Butoxors [25]

Re-read and go back and look for A & B and then whatever A & B is solve for it and then get your answer

4 0

3 years ago

If you boil a sample of water, the steam that results will have: Select the correct answer below: less mass than the water more

Over [174]

Answer: less mass than the water

Explanation:

8 0

3 years ago

For many weak acid or weak base calculations, you can use a simplifying assumption to avoid solving quadratic equations. Classif

shtirl [24]

Answer:

a. not valid

b. valid

c. not valid

d. valid

e. not valid

Explanation:

The assumption to avoid solving the quadratic equation for the calculation of [H⁺] and [OH⁻] involved in the equilibria of weak acids and bases ( small Ka and Kb) is valid as long as the value obtained from the shortcut is less than 5 % or less of the original acid or base concentration.

For a general monoprotic acid, as in this question, the equlibria is:

HA + H₂O ⇄ H₃O⁺ + A⁻ Ka = [H₃O⁺][A⁻]/[HA]

To determine the concentrations at equilibrium we are going to setupup the ICE table:

[HA] [H₃O] [A⁻]

Initial [HA]₀ 0 0

Change - x +x +x

Equil [HA]₀ - x x x

Ka = x² / [HA]₀ - x

Here is where we make our simplification of approximating [HA]₀ - x to the original acid concentration, [HA]₀, assuming x is much less than [HA] since HA is a weak acid.

To answer our questions we will solve for x,and then can compare it to the initial HA concentration.

Lets now perform our calculations.

(a) x = √ (0.01 x 1x 10⁻⁴) = 1 x 10⁻³ M = [H₃O⁺]

% = 1 x 10⁻³/.01 x 100 = 10%

The assumption is not valid.

(b) x = √ (0.01 x 1x 10⁻⁵) = 3.2 x 10⁻⁴ M = [H₃O⁺]

% = 3.2 x 10⁻⁴ /0.01 x 100 = 3.2 %

The assumption is valid since the criteria of 5 % or less has been met.

(c) x = √ (0.1 x 1x 10⁻³) = 1.0 x 10⁻² M = [H₃O⁺]

% = 1.0 x 10⁻² /0.1 x 100 = 10 %

The assumption is not valid, we wiould have to solve the quadratic equation.

(d) x = √ (1 x 1x 10⁻³) = 3.2 x 10⁻² M = [H₃O⁺]

% = 3.2 x 10⁻² / 1 x 100 = 3.2

The assumption is valid.

(e) x = √ (0.001 x 1x 10⁻⁵) =1.0 x 10⁻⁴ M = [H₃O⁺]

% = 1.0 x 10⁻⁴ / .001 = 10 %

The assumption is not valid and one has to solve the quadratic equation.

7 0

3 years ago