Answer:
V = 365.54 mL
Explanation:
Given that,
The density of chloroform, d = 1.48 g/mL
The mass of chloroform, m = 541 g
We need to find the volume of chloroform.
We know that,
Density = mass/volume
So,
So, the volume of chloroform is 365.54 mL.
<u>Answer:</u> The true statements are 
for an endothermic reaction is positive, a combustion reaction is exothermic and when energy is transferred as heat from the system to the surroundings, is negative.
<u>Explanation:</u>
There are 2 types of chemical reactions categorized into heat change:
- <u>Endothermic reactions:</u> These reactions are defined as the reactions in which energy is absorbed by the system from the surroundings. The for these reactions is always positive. For Example: Changing of water into water vapor.
- <u>Exothermic reactions:</u> These reactions are defined as the reactions in which energy is released by the system to the surroundings. The for these reactions is always negative. For Example: Combustion reactions.
Combustion reactions are defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water. Heat is released during these reactions. Thus, it is considered as exothermic reactions.
Hence, the true statements are for an endothermic reaction is positive, a combustion reaction is exothermic and when energy is transferred as heat from the system to the surroundings, is negative.
Answer:
92.9%
Explanation:
You have been given the actual yield of the reaction. First, you need to find the theoretical yield of the reaction. To do this, you need to (1) convert grams Fe₂O₃ to moles Fe₂O₃ (via molar mass from periodic table values), then (2) convert moles Fe₂O₃ to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass).
Once you have found the theoretical yield, you need to use the percent yield equation to calculate the final answer. This number should have 3 sig figs to match the given values.
<u>(Step 1)</u>
Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)
Molar Mass (Fe₂O₃): 159.684 g/mol
1 Fe₂O₃(s) + 3 CO(g) ---> 2 Fe(s) + 3 CO₂(g)
Molar Mass (Fe): 55.845 g/mol
50.0 g Fe₂O₃ 1 mole 2 moles Fe 55.845 g
-------------------- x ------------------ x --------------------- x ---------------- = 35.0 g Fe
159.684 g 1 mole Fe₂O₃ 1 mole
<u>(Step 2)</u>
Actual Yield
Percent Yield = --------------------------- x 100%
Theoretical Yield
32.5 g Fe
Percent Yield = ---------------------- x 100% = 92.9%
35.0 g Fe
243.92J
Explanation:
Given parameters:
Mass of the aluminum cup = 42.14g
Initial temperature of the cup, t₁ = 20°C
Final temperature of the cup t₂ = 26.41°C
Specific heat capacity of aluminium = 0.903 J g⁻¹ °C⁻¹
Unknown:
Change in heat of the aluminium cup, q = ?
Solution:
The heat lost during the experiment is the heat gained by the aluminum cup.
The quantity of heat is found using the expression below:
q = m C Δt
m is the mass of the cup
C is the specific heat of the cup
Δt is the change in heat
q = 42.14 x 0.903 x (26.41 - 20) = 42.14 x 0.903 x 6.41
q = 243.92J
Learn more:
Specific heat capacity brainly.com/question/7210400
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