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sergiy2304 [10]
3 years ago
10

Line segment ABCD is split into unequal segments by points A, B, C, and D. The length of segment AD is 28 cm, and the distance b

etween the midpoints of segments AB and CD is 16 cm. Find the length of segment BC.
Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

4 cm

Step-by-step explanation:

The midpoint segment has length ...

... L = AB/2 + BC + CD/2 = 16 cm

The entire segment has length ...

... AD = AB + BC + CD = 28 cm

If we subtract AD from 2L, we have ...

... 2L - AD - 2L = 2(AB/2 +BC + CD/2) - (AB +BC +CD) = 2(16 cm) -28 cm = 4 cm

... AB +2BC + CD -AB -BC -CD = 4 cm . . . . remove parentheses

... BC = 4 cm . . . . simplify

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Step-by-step explanation:

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What is the next item in the sequence −10,−3,4,11
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▹ Answer

<em>18</em>

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1. Select all the triangles that can be rotated to match up with Triangle 1. Triangle 1 A B D C С​
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8 0
3 years ago
A bucket contains 40 red balls, 25 black balls, and 35 white balls. Two balls are drawn at random. What is the probability that
Lyrx [107]

Answer:

Probability = \frac{1}{5} or Probability = 0.2

Step-by-step explanation:

Given

Black = 25

White = 35

Red = 40

Required

Determine the probability of selecting Black and Red

First, we need to calculate the number of red and black balls

The probability is calculated as thus:

Probability = P(Black\ and \ Red) \ or\ P(Red\ and \ Black)

Convert to mathematical expressions

Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]

Solve for each probaility;

P(Black) = \frac{Black}{Total} = \frac{25}{100}

P(Red) = \frac{Red}{Total} = \frac{40}{100}

So, we have:

Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]Probability = [\frac{25}{100} *\frac{40}{100}] + [\frac{40}{100} *\frac{25}{100}]

Probability = [\frac{1000}{10000}] + [\frac{1000}{10000}]

Probability = [\frac{1}{10}] + [\frac{1}{10}]

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Probability = \frac{2}{10}

Probability = \frac{1}{5}

or

Probability = 0.2

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