<span>an equation that expresses the gross weight of an aircraft as a function of its landing speed will be given as follows:
</span><span> V= √1.223w
we make w the subject of the equation, we start by dividing both squaring both sides:
</span>V²=(√1.223w)²
V²=1.223w
next we divide both sides by 1.223 to get :
V²/1.223=1.223w/1.223
w=V²/1.223
hence the answer will be w=V²/1.223
Start off by knowing that the two triangle are congruent. By knowing this you can turn the given numbers into fractions.
9/72 = 7/7x+7
then cross multiply, which equals
63x + 63 = 504
then solve this equation
63x = 441 - subtract 63 from both sides
x = 7 - divide by 63 from both sides
so your answer is x=7
First, notice that:
![2\tan (\frac{x}{2})=2\cdot(\pm\sqrt[]{\frac{1-cosx}{1+\cos x})}](https://tex.z-dn.net/?f=2%5Ctan%20%28%5Cfrac%7Bx%7D%7B2%7D%29%3D2%5Ccdot%28%5Cpm%5Csqrt%5B%5D%7B%5Cfrac%7B1-cosx%7D%7B1%2B%5Ccos%20x%7D%29%7D)
And in the denominator we have:
then, we have on the original expression:
![\begin{gathered} \frac{2\tan(\frac{x}{2})}{1+\tan^2(\frac{x}{2})}=\frac{2\cdot\pm\sqrt[]{\frac{1-\cos x}{1+cosx}}}{\frac{2}{1+\cos x}}=\frac{2\cdot(\pm\sqrt[]{1-cosx})\cdot(1+\cos x)}{2\cdot(\sqrt[]{1+cosx})} \\ =(\sqrt[]{1-\cos x})\cdot(\sqrt[]{1+\cos x})=\sqrt[]{(1-\cos x)(1+\cos x)} \\ =\sqrt[]{1-\cos^2x}=\sqrt[]{\sin^2x}=\sin x \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B2%5Ctan%28%5Cfrac%7Bx%7D%7B2%7D%29%7D%7B1%2B%5Ctan%5E2%28%5Cfrac%7Bx%7D%7B2%7D%29%7D%3D%5Cfrac%7B2%5Ccdot%5Cpm%5Csqrt%5B%5D%7B%5Cfrac%7B1-%5Ccos%20x%7D%7B1%2Bcosx%7D%7D%7D%7B%5Cfrac%7B2%7D%7B1%2B%5Ccos%20x%7D%7D%3D%5Cfrac%7B2%5Ccdot%28%5Cpm%5Csqrt%5B%5D%7B1-cosx%7D%29%5Ccdot%281%2B%5Ccos%20x%29%7D%7B2%5Ccdot%28%5Csqrt%5B%5D%7B1%2Bcosx%7D%29%7D%20%5C%5C%20%3D%28%5Csqrt%5B%5D%7B1-%5Ccos%20x%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B1%2B%5Ccos%20x%7D%29%3D%5Csqrt%5B%5D%7B%281-%5Ccos%20x%29%281%2B%5Ccos%20x%29%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B1-%5Ccos%5E2x%7D%3D%5Csqrt%5B%5D%7B%5Csin%5E2x%7D%3D%5Csin%20x%20%5Cend%7Bgathered%7D)
therefore, the identity equals to sinx
Answer:
I believe it is Option 1
Step-by-step explanation:
Since the fourth root of 81 will be 3 and of 16 will be 2.
Lets divide this prism into two parts. The bottom part has dimensions of 15mm length x 5mm width x 7mm height.
The bottom is 15x5x7 = 525 cubic mm.
The top part has dimensions of 9mm length (I got this by subtracting the 3mm on each side that the top is shorter than the bottom.. 15-3x2) x 5mm width x 3mm height.
The top is 9x5x3 = 135 cubic mm.
Added together ... 525 + 135 = 660 cubic mm = the total area of the prism.
Hope this helps
