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2 years ago

9

If you can help 1-12 that’s great if not just help with what you can thanks

1 answer:

bearhunter [10]2 years ago

5 0

(1. -2) (2. 0) (3. 6) (4. 3)

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What is the answer to this integers (-10)(-3)(0)

damaskus [11]

ZERO

as it is eventually multiplied by 0

4 0

3 years ago

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Express the negations of each of these statements so that all negation symbols immediately precede predicates. a) ∀x∃y∀zT(x, y,

Gnesinka [82]

Answer:

a) ∀x∃y ¬∀zT(x, y, z)

∀x∃y ∃z ¬T(x, y, z)

b) ∀x¬[∃y (P(x, y) ∨ Q(x, y))]

∀x∀y ¬ [P(x, y) ∨ Q(x, y)]

∀x∀y [¬P(x, y) ^ ¬Q(x, y)]

c) ∀x ¬∃y (P(x, y) ^ ∃zR(x, y, z))

∀x ∀y ¬(P(x, y) ^ ∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ¬∃zR(x, y, z))

∀x ∀y (¬P(x, y) v ∀z¬R(x, y, z))

d) ∀x¬∃y (P(x, y) → Q(x, y))

∀x∀y ¬(P(x, y) → Q(x, y))

∀x∀y (¬P(x, y) ^ Q(x, y))

3 0

2 years ago

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"Solve the system using the elimination method. Show work."

Dafna1 [17]

Solution in an attachment.

x = -4; y = -2; z = 4

6 0

2 years ago

PLS HELP ME AND SHOW WORK.

Alex17521 [72]

Answer:

$4 = (x + 7 {)}^{2} + (y - 3 {)}^{2}$

Step-by-step explanation:

equation of a circle

${r}^{2} = (x - {h} )^{2} + (y - {k)}^{2}$

we know the center is (-7, 3)

the radius is 2

we replace (h,k) with the center coordinates

and input the radius

${2}^{2} = (x -( - 7)) ^{2} + (y - 3)^{2}$

simplify to this:

$4 = (x + 7 {)}^{2} + (y - 3 {)}^{2}$

3 0

3 years ago

Find the value of x. Then tell whether the side lengths form a Pythagorean triple.<br> 12<br> 16

Neko [114]

Answer:

x=20

The side lengths form a 345 triple

Step-by-step explanation:

345 triangles have 3, 4, and 5 as their lengths

If we divide all of them by 4 we get..

12/4=3 and 16/4=4 that means we are missing 5

5*4=20

8 0

2 years ago