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HACTEHA [7]
3 years ago
9

If you can help 1-12 that’s great if not just help with what you can thanks

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0
(1. -2) (2. 0) (3. 6) (4. 3)





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Show step by step explanation 9x-(6x+6)=5x-30
Shtirlitz [24]

Answer:

x=-18

Step-by-step explanation:

multiply the invisible 1 outside the parenthesis with the numbers inside. next combine like terms on the left side of the equation. then simplify the equation. then divide -2x by -36. then multiply -1 to your answer and the outcome gives -18

7 0
3 years ago
How do I solve 5x - 4x^2
Sever21 [200]

Answer:

If you are asking,

5x - 4x^2=0

x(5-4x)=0

Either,

x=0

or,

5-4x=0

x=5/4

If factor,

5x - 4x^2

x(5-4x)

If difference,

5x - 4x^2

The same as they are not like terms.

7 0
3 years ago
What the expression has the factor of (H +2)
katen-ka-za [31]

Answer:

a - h^2 + h - 2

Step-by-step explanation:

To find the expression with factor h + 2, I solved it the usual way I would

6 0
3 years ago
CAN SOMEONE PLSSSSS ANSWER BOTH OF THESE QUESTIONS<br> I WILL MARK BRAINLIEST
Margaret [11]

Answer: B and C

Step-by-step explanation:

404 + 50 + 50 = 504

you are buying  144 magazines total

504/144 = cost of one magazine

cost of one = 3.50

you are paying $60 a year for 12 years

60 x 12 = 720

720/144 = 5

5 - 3.50 = 1.50

2.

120x + 180x = 1080

300x = 1080

x = 1080/300

x = 3.6

3.6 x 60 = 216

3 0
2 years ago
Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
6 0
3 years ago
Read 2 more answers
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