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2 years ago

19. When baking a cake, you have a choice of the following pans:

Mathematics

2 answers:

dimaraw [331]2 years ago

7 0

The answer is

round cake - 82.42 in²

rectangular cake - 114 in²

Round cake:

d = 7 in

r = d/2 = 7 in / 2 = 3.5 in

h = 2 in

The surface are of a cylinder is:

A = 2πr² + 2πrh

The surface are of the round cake (which is actually a cylindrical cake) excluding the bottom is:

A = 2πr² + 2πrh - πr²

A = πr² + 2πrh

A = 3.14 * 3.5² + 2 * 3.14 * 3.5 * 2

= 38.46 + 43.96

= 82.42 in²

Rectangular cake:

w = 6 in

l = 9 in

h = 2 in

The surface are of a rectangle is:

A = 2wl + 2wh + 2lh

The surface are of the rectangular cake excluding the bottom is:

A = 2wl + 2wh + 2lh - wl

A = wl + 2wh + 2lh

A = 6 * 9 + 2 * 6 * 2 + 2 * 9 * 2

= 54 + 24 + 36

= 114 in²

Step-by-step explanation: This answer is not mine but JcAlmighty’s so all credits go to them.

melomori [17]2 years ago

3 0

114 ....................

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Which are removable discontinuities?

Afina-wow [57]

Answer:

Step-by-step explanation:

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2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

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DochEvi [55]

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2 years ago

A. 4+2(5)+(−3) b. 4+2[5+(−3)] PLEASE- I NEED HELP!!!

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2 years ago

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ValentinkaMS [17]

Answer:

He can fill 3 bags

Step-by-step explanation:

You would first make them have a common denominator so you would have 2/8 instead of 1/4 then you would do 6/8 divided by 2/8 to get 3

1/4 = 2/8

6/8 divided by 2/8 = 3

7 0

2 years ago

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