Ask question

Ask question

All categories

3 years ago

14

Help with number 2 plz

1 answer:

arlik [135]3 years ago

7 0

Try drawing the ball in motion by using arrows to point which direction itll go.

You might be interested in

How is sound detected by the brain

asambeis [7]

I think it's A electrical impulses from the ear

4 0

4 years ago

Read 2 more answers

Cual es el esfuerzo que puede provocar un corte en el material

jolli1 [7]

Answer:

El esfuerzo cortante, de corte, de cizalla o de cortadura es el esfuerzo interno o resultante de las tensiones paralelas a la sección transversal de un prisma mecánico como por ejemplo una viga o un pilar. Se designa variadamente como T, V o Q.

Este tipo de solicitación formado por tensiones paralelas está directamente asociado a la tensión cortante. Para una pieza prismática se relaciona con la tensión cortante mediante la relación:

(1){\displaystyle Q_{y}=\int _{\Sigma }\tau _{xy}\ dydz,\qquad Q_{z}=\int _{\Sigma }\tau _{xz}\ dydz,\qquad Q={\sqrt {Q_{y}^{2}+Q_{z}^{2}}}}

Para una viga recta para la que sea válida la teoría de Euler-Bernoulli se tiene la siguiente relación entre las componentes del esfuerzo cortante y el momento flector:

5 0

4 years ago

The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the

nataly862011 [7]

Answer with Explanation:

Let rest mass $m_0$ at point P at distance x from center of the planet, along a line connecting the centers of planet and the moon.

Mass of moon=m

Distance between the center of moon and center of planet=D

Mass of planet=M

We are given that net force on an object will be zero

a.We have to derive an expression for x in terms of m, M and D.

We know that gravitational force= $\frac{GmM}{r^2}$

Distance of P from moon=D-x

$F_m$ =Force applied on rest mass due to m

$F_m$ =Force on rest mass due to mas M

$F_M=F_m$ because net force is equal to 0.

$F_m=F_M$

$\frac{Gm_0m}{(D-x)^2}=\frac{Gm_0M}{x^2}$

$\frac{m}{(D-x)^2}=\frac{M}{x^2}$

$\frac{x^2}{(D-x)^2}=\frac{M}{m}$

$\frac{x}{D-x}=\sqrt{\frac{M}{m}}$

Let $R=\sqrt{\frac{M}{m}}$

Then, $\frac{x}{D-x}=R$

$x=DR-xR$

$x+xR=DR$

$x(1+R)=DR$

$x=\frac{DR}{1+R}$

b.We have to find the ratio R of the mass of the mass of the planet to the mass of the moon when x= $\frac{2}{3}D$

Net force is zero

$F_m=F_M$

$\frac{Gm_0m}{(D-\frac{2}{3}D)^2}=\frac{Gm_0M}{\frac{4}{9}D^2}$

$\frac{m}{\frac{D^2}{9}}=\frac{9M}{4D^2}$

$\frac{M}{m}=4$

Hence, the ratio R of the mass of the planet to the mass of the moon=4:1

8 0

4 years ago

Distinguish the steps in the process of stopping a tractor, keeping them in proper order.

weeeeeb [17]

Ahhh, there aren’t option to work with :v
Try writing them down here thnx

7 0

3 years ago

Read 2 more answers

A 0.280-kg volleyball approaches a player horizontally with a speed of 15.0 m/s. The player strikes the ball with her fist and c

Genrish500 [490]

Answer:

Impulse = 10.36 kg m/s

average force = 172.667 N

Explanation:

given data

mass = 0.280 kg

speed = 15.0 m/s

speed = 22.0 m/s

to find out

impulse and magnitude of the average force

solution

we know that Impulse is change in momentum that is

initial momentum = mass × speed ..........1

initial momentum = 0.28 × (15)

initial momentum = 4.2 kg m/s

Final momentum = mass × speed ..........2

Final momentum = 0.28 × (-22)

Final momentum = -6.16 kg m/s

so now we get Impulse that is

Impulse = 4.2 - (-6.16)

Impulse = 10.36 kg m/s

and

average force will be

average force = impulse ÷ time

average force = $\frac{10.36}{0.060}$

average force = 172.667 N

6 0

3 years ago