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3 years ago

The answer to number 9 please

Physics

1 answer:

Delicious77 [7]3 years ago

7 0

The magnitude is doubled. The direction doesn't change.

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C. 400 km/min

Nataly_w [17]

A is the answer i hope

5 0

4 years ago

A conductor of radius r, length and resistivity ρ has resistance r. what is the new resistance if it is stretched to 4 times its

max2010maxim [7]

The resistance of a conductor is given by
$R= \frac{\rho L}{A}$
where L is the length of the wire, $\rho$ the resistivity of the material and A the cross-sectional area.

We can see that if all the other quantities do not change, if the new length of the conductor is 4 times the original length: $L'=4 L$ , then the new resistance is also 4 times the original value:
$R'= \frac{\rho L'}{A}= \frac{\rho 4 L}{A}=4 \frac{\rho L}{A}=4 R$

7 0

4 years ago

An object of mass 2 kg travels through outer space in a straight line at a constant

slava [35]

Answer:

b. It is subject to a net force of zero

Explanation:

F = m*a

F = force

m = mass

a = acceleration

Since the object is moving at a constant velocity not speeding up or slowing down and moving in a sight line. All the forces that are acting on the object are canceling each other out so the answer is:

b. It is subject to a net force of zero

7 0

3 years ago

A 2 kg blob of sticky putty is thrown with a velocity of 5 m/s at a 1 kg doll. After impact, the putty sticks to the doll and co

kow [346]

Answer:3.33 m/s

Explanation:

Given

mass of Putty M=2 kg

the velocity of bob u=5 m/s

mass of doll m=1 kg

As there is no external force acting so linear momentum is conserved

Mu=(M+m)v

where v=common velocity of putty and doll after the impact

$2\times 5=(2+1)v\\v=\dfrac{10}{3}\ m/s\approx3.33\ m/s$

6 0

3 years ago

Two identical freight cars roll without friction (one at 1 m/s, the other at 2 m/s) toward each other on a level track. They col

Kazeer [188]

Answer:

They collide, couple together, and roll away in the direction that <u>the 2m/s car was rolling in.</u>

Explanation:

We should start off with stating that the conservation of momentum is used here.

Momentum = mass * speed

Since, mass of both freight cars is the same, the speed determines which has more momentum.

Thus, the momentum of the 2 m/s freight car is twice that of the 1 m/s freight car.

The final speed is calculated as below:

mass * (velocity of first freight car) + mass * (velocity of second freight car) = (mass of both freight cars) * final velocity

(m * V1) + (m * V2) = (2m * V)

Let's substitute the velocities 1m/s for the first car, and - 2m/s for the second. (since the second is opposite in direction)

We get:

$m*1 + m*(-2) = 2m*V$

solving this we get:

V = - 0.5 m/s

Thus we can see that both cars will roll away in the direction that the 2 m/s car was going in. (because of the negative sign in the answer)

7 0

4 years ago