Explanation:
Load (l) = 680N
Effort (E) = 500N
Length slope (l) = 12m
Height slope (h) = 8 m
Output = load * height
680 *8 = 5.44 *103 J
The Input = effort * length = 500 *12 = 6000J
the Mechanical advantage (M.A) = load effort= 600500=1.36
the Velocity ratio (V.R) =lh=128 = 1.5
the Efficiency =M.A100%V.R= 90.6%
I'm not good with math but I think it is 23.4
Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:
The minimun wall thickness:
<span>Fusion produces large amounts of energy, and the fuel is found on Earth.</span>
Answer:
1.56 m/s
Explanation:
For East direction, the 6 blocks is equivalent to 6*100=600 m
For West direction, 8 blocks is equivalent to 8*100=800 m
Speed is given by s=d/t where s is speed, d is distance covered and t is time taken
Total distance is 600+800=1400m
Time taken is 15 mins, converted to seconds will be 15*60=900 s
Speed, s=1400/900=1.5555555555555 m/s rounded off as 1.56 m/s
