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4 years ago

Cual es el esfuerzo que puede provocar un corte en el material

Physics

1 answer:

jolli1 [7]4 years ago

5 0

Answer:

El esfuerzo cortante, de corte, de cizalla o de cortadura es el esfuerzo interno o resultante de las tensiones paralelas a la sección transversal de un prisma mecánico como por ejemplo una viga o un pilar. Se designa variadamente como T, V o Q.

Este tipo de solicitación formado por tensiones paralelas está directamente asociado a la tensión cortante. Para una pieza prismática se relaciona con la tensión cortante mediante la relación:

(1){\displaystyle Q_{y}=\int _{\Sigma }\tau _{xy}\ dydz,\qquad Q_{z}=\int _{\Sigma }\tau _{xz}\ dydz,\qquad Q={\sqrt {Q_{y}^{2}+Q_{z}^{2}}}}

Para una viga recta para la que sea válida la teoría de Euler-Bernoulli se tiene la siguiente relación entre las componentes del esfuerzo cortante y el momento flector:

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PLS HELP :) GIVING BRAINLIEST SIMPLE SCIENCE QUESTION HELPS PLSSSS

raketka [301]

OMG ITS B ITS B I HOPE I HELPED U

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3 years ago

A 1400 kg car driving at 25 m/s slams on its brakes. The coefficient of kinetic friction between the tires and the road is 0.7.

tamaranim1 [39]

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

mass of the car, m = 1400 kg
Initial velocity of the car, u = 25 m/s
coefficient of kinetic friction, μ = 0.7

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

$F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s$

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

Learn more here:brainly.com/question/19887955

5 0

3 years ago

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

Sedaia [141]

Answer:

$a_2\ =\ -33.65\ m/s^2$

Explanation:

Given,

For the first rocket,

Initial velocity of the first rocket A = $u_1\ =\ 4600\ m/s.$

Acceleration of the first rocket = $a_1\ =\ -18\ m/s^2$

For the second rocket,

Initial velocity of the second rocket B = $u_2\ =\ 8200 m/s.$
Displacement of both the rockets A and B = s = 0 m

Fro the first rocket,

Let 't' be the time taken by the first rocket A for whole the displacement

$\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec$

Let $a_2$ be the acceleration of the second rocket B for the same time interval

from the kinematics,

$\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\$

$\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2$

Hence the acceleration of the second rocket B is -33.65\ m/s^2.

6 0

3 years ago

Crystallization of solids

Deffense [45]

Answer:

A separation technique to separate solids from a solution. Crystallization can be defined as the process through which the atoms/molecules of a substance arrange themselves in a well-defined three-dimensional lattice and consequently, minimize the overall energy of the system.

Explanation:

3 0

3 years ago

Read 2 more answers

At which temperature does the motion of atoms and molecules stop?

Scorpion4ik [409]

Answer:

0 Kelvin

Explanation:

Atoms in absolute temperature get approximatelly motionless since 0 Kelvin is -273 degrees Celcius. The kinetic energy of atoms/particles in matter has the possible lowest value ( almost zero), so that there is nothing colder than 0 Kelvin.

4 0

3 years ago