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Artyom0805 [142]
2 years ago
13

Simplify each expression (Please)

Mathematics
1 answer:
rewona [7]2 years ago
3 0
2(p+8)+4= 2p+20

(18+ t)(-3)+9=t+24

30q(2)=60q

-5(n+16)-7= -5n-87
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Write and equivalent exspression to 8k-(5+2k) without parentheses then simplify
Nezavi [6.7K]

Answer:

6k - 5

Step-by-step explanation:

8k-(5+2k)

8k -5 -2k

6k - 5

3 0
3 years ago
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Question 2 of 10
iVinArrow [24]

Answer:

option C is correct

x^4 - x^2 - 2.5

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3 years ago
Write the rate as a unit rate. 44 points in 4 quarters
Margaret [11]

Answer:

44 p points in 4 quarters = llets per Qtr.

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3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
How do you change 44/15 into a mixed number
torisob [31]
First you can divide 44 into 15, which is two with a remainder of 14 so that means the mixed number would be 2 and 14/15
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5 0
3 years ago
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