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3 years ago

101

Mathematics

1 answer:

Anna35 [415]3 years ago

3 0

Answer:

second option

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (4, 5) and r = 2 , thus

(x - 4)² + (y - 5)² = 2², that is

(x - 4)² + (y - 5)² = 4 ← equation of circle

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A line passes through the point (-8,8) and has a slope of -5/4

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3 years ago

For what value(s) of k will the relation not be a function

skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

$R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]$

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$k-8.3+2.4k=-\frac{3}{4} k$

$3.4k-8.3=-\frac{3}{4}k$

$3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10$

$4k-83=-\frac{15}{2}k$

$34k=-\frac{15}{2}k+83$

$\frac{83}{2}k=83$

$83k=166$

$k=2$ ............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

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$2-|k+1|=-6$

$2-\left|k+1\right|-2=-6-2$

$-\left|k+1\right|=-8$

$\left|k+1\right|=8$

Since, this is absolute function

so, we can break it into two parts

$|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a$

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$k=-9\quad \mathrm{or}\quad \:k=7$ ...............Answer

5 0

3 years ago

Reflect quadrilateral SQRT over the y-axis. Then translate the new quadrilateral 3 units to the right. What are the coordinates

wel

Answer: S(-5;3) Q(-2;2) R(-3;-2) T(-6;-1)

When reflected over the y-axis, their x values will change sign

S(5;3) Q(2;2) R(3;-2) T(6;-1)

Translate 3 units to the right, their x values will increase by 3

S(8;3) Q(5;2) R(6;-2) T(9;-1)

Step-by-step explanation:

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2 years ago

Read 2 more answers

Solve for y<br> 2(3 + 3y) + y = 11

garik1379 [7]

<h2><u>EQUATION</u></h2><h3>Exercise</h3>

2(3 + 3y) + y = 11

First, apply the distributive property:

2(3 + 3y) + y = 11

6 + 6y + y = 11

6 + 7y = 11

Substract 6 from both sides:

6 - 6 + 7y = 11 - 6

7y = 5

Divide both sides by 7:

$\dfrac{7y}{7} = \dfrac{5}{7}$

$\boxed{y = \dfrac{5}{7}}$

<h3><u>Answer</u>. The value of y = 5/7.</h3>

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2 years ago

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almond37 [142]

Answer:

$=14a^5+14a^4-10a^3-16a$

Step-by-step explanation:

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$\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a$

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2 years ago