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iVinArrow [24]
4 years ago
15

i don't know how to solve this problem i think i can dl the firts part but the 2nd one i don't know what x means the question sa

id" evaluate the expressions below for the given values" "-2x2+1 for x=-3" the firts part gives me 9 bit idk what to do with the "for x=-3"

Mathematics
1 answer:
atroni [7]4 years ago
4 0

In the equation -2x^2 + 1
We're supposed to substitute x by the given value which is -3 in this case.
-2x^2 + 1 = -2(-3)^2 + 1
= -2(9) + 1
= -18 + 1
= -17

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Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
3 years ago
Answers are needed urgently..ty​
SIZIF [17.4K]

Angle <QAB is =15° because the opposite angles of an isosceles triangle are equal.

The length of the straight line AB = 80cm

<h3>Calculation of angle of a triangle</h3>

The angle at a point = 360°

Angle AQB= 360 - 210° = 150

But the angle that makes up a triangle= 180°

180-150= 30°

But <QAB = <QBA because triangle AQB is an isosceles triangle.

30/2 = 15°

To calculate the length of the straight line the following is carried out using the sine laws.

a/ sina, = b sinb

a= 8cm, sin a { sin 15)

b= ? , sin B = 150

make b the subject formula;

8/sin15= b/sin 150

b= 8 × sin 150/sin 15

b= 80cm

Learn more about isosceles triangle here:

brainly.com/question/25812711

#SPJ1

7 0
2 years ago
Domain and Range for the graph
Lena [83]

Answer:

its gos up

Step-by-step explanation:

think it's not hard

3 0
3 years ago
Solve the equation <br><br> 3x+15=3(x+5)
DaniilM [7]

Answer:

All real numbers are solutions.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A quadrilateral has no pairs of parallel sides.what two shapes could be it
Basile [38]

Answer:

All trapezoids are quadrilaterals.

Step-by-step explanation:

Incorrect. Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. A trapezoid can never be a parallelogram. The correct answer is that all trapezoids are quadrilaterals.

8 0
3 years ago
Read 2 more answers
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