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irakobra [83]
3 years ago
5

In a large flock of 6520 sheep, 53 of them have yellow fat while the rest of the flock members have white fat. Yellow fat is inh

erited as a recessive trait. Assuming the population is in Hardy-Weinberg equilibrium, how many of the white fat sheep will have a homozygous dominant genotype?
Biology
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

number of sheep with homozygous dominant white fat genotype = 5399

Explanation:

If p = frequency of dominant allele and q= frequency of recessive allele

According to Hardy-Weinberg equilibrium:

p + q =1 and p² + 2pq + q² = 1

where p² = frequency of homozygous dominant genotype

q²= frequency of homozygous recessive genotype

and 2pq= frequency of heterozygous genotype

Here,

q² = 53/6520= 0.0081

q = √0.0081 = 0.09

p = 1-q = 1-0.09= 0.91

So, p² = 0.91² = 0.8281

number of sheep with homozygous dominant white fat genotype= 0.8281*6520 = 5399

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