Answer:
42,5 mL
Explanation:
We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.

<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>
The first step is to have the same measurment unit so we need to convert 345 µg to mg.
we know that 1 µg equals 0,001 g, hence:

now the final volume is 0,345 mg protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula


Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL

So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)
Answer:
Fungi
Explanation:
Fungi are an example of saprotrophs i.e. organisms who live and feed on dead organic matter. Saprotrophic nutrition is described as chemoheterotrophic extracellular digestion. It involves the extracellular release of digestive enzymes on the organic matter. The enzymes break down the organic matter into a simpler form, which is then absorbed by the fungus.
Fossil evidence, and biographical evidence.