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3 years ago

X + y = 6 2x + y = 4 Solve the system of equations.

Mathematics

2 answers:

Debora [2.8K]3 years ago

8 0

(X,Y) = (-2,8) this the answer

Shtirlitz [24]3 years ago

4 0

X,y= -2,8 i know you have the answer but i need to answer one so i can ask another question do i answered this one

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Solve this system of linear equations.separate the x- and y-value with a comma. -6x=-4-y -7x=-22+y.

scZoUnD [109]

Answer:

(2,8)

Step-by-step explanation:

Add them together to get rid of the y.

-6x = -4 - y

-7x = -22 + y

-13x = -26

Then solve for x.

-13x/-13 = -26/-13

x = 2

Now plug in the x value into either equation and solve for y.

-7(2) = -22 + y

-14 = -22 + y

-14 + 22 = -22 + 22 + y

8 = y

So...

x = 2

y = 8

(2,8)

8 0

3 years ago

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Can someone help me and explain? I will mark brainlest. ♡

Sedbober [7]

Answer:

$p'(4) = -3$

$q'(8) = \frac{1}{4}\\$

Step-by-step explanation:

For p'(4):

$p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)$

$p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3$

For q'(8):

$q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}$

$q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}$

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3 years ago

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Radda [10]

Answer:

112 if you don't include the triangle sides as they are not necessary, but 124 if you include one triangle and 136 if you include both triangle sides

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A set of cards contains cards numbered 1-10. Mrs. Jacobs class is conducting an experiment in which a card Is drawn from the pil

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Korvikt [17]

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