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2 years ago

Work out the area of a rectangle with base,b= 32mm and perimeter,P= 78mm.

Mathematics

1 answer:

Nataly_w [17]2 years ago

7 0

Answer:

224

Step-by-step explanation:

b = 32, h = 7 is the solution to P = 78. Hence, 7*32 = 224 is the answer

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Two positive integers have a product of 200.

sattari [20]

Since 200 is a constant, of x, move 200 out of the integral. 200x+c. Constant is a fixed value that does not change.

IF YOU LIKE MY ANSWER PLS GIVE ME BRAINLIEST!!

3 0

2 years ago

What the LCM of 32 and 45

ivann1987 [24]

1,440 is the answer i learned lcm last friday

8 0

3 years ago

The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

Nata [24]

Answer:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

Let X the random variable that represent the compressive strength of concrete of a population, and for this case we know the distribution for X is given by:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

7 0

3 years ago

Points that two lines pass through are given in the table. Match each point of intersection to the correct pair of lines.

Volgvan

(2,0)(0,2
(-1,-3)(-3,-1)
(-1,3) (1,0)

3 0

3 years ago

If everyone in the world (about 8 billion people) played a giant game of rock, paper, scissors, how many games would need to be

Llana [10]

Answer:

TOO MANY

Step-by-step explanation:

so if people are playing with 2 people at a time then it would go like this...

it would start with 4 billion v.s. 4 billion.

then it would narrow down to 2 billion v.s. 2 billion.

then it would go down to 1 billion v.s. 1 billion.

then i would go down to 500 million v.s. 500 million.

then it would go down to 250 million v.s. 250 million.

Then it would go down to 125 million v.s. 125 million.

then it would go down to 62,500 v.s 62,500.

then it would go down to 31,250 v.s. 31,250.

then it would go down to 15,625 v.s. 15,625.

then it would go down to 7,812 v.s. 7812.

then it would go down to 3,906 v.s. 3906.

then it would go down to 1,953 v.s. 1953.

then it would go down to 976 v.s. 976.

then it would go down to 488 v.s. 488.

then it would go down to 244 v.s. 244.

then it would go down to 122 v.s. 122.

then it would go down to 61 v.s. 61.

then it would go down to 30 v.s. 30.

then it would go down to 15 vs 15.

then it would go down to 7 vs 7.

then it would go down to 3 vs 3.

then it would go down to 1 vs 1.

so it would take 22 matches if the matches were conducted like tournements.

6 0

2 years ago