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dolphi86 [110]
3 years ago
14

Which expression can be used to find 20 percent of 927

Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

927/5

Step-by-step explanation:

100%/20=5 so just divide by 5

Gennadij [26K]3 years ago
7 0

Answer:

0.2×92=18.4

Step-by-step explanation:

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77julia77 [94]
H would be your answer (9x2)+(14x4)=74
8 0
3 years ago
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If EG=50 , and point F is 2/5 of the way between e and g,find the value FG A.30 B.25 C.40 D.20
noname [10]

Answer:

b is the ans

Step-by-step explanation:

6 0
2 years ago
Rosa and her friends are eating out for dinner. the bill was $30.12. they want to leave a 19% tip.
FromTheMoon [43]

Answer:

35.84

Step-by-step explanation:

You would take 19% of 30.12$ by doing 30.12x0.19 to get 5.72.

you then add 5.72 to 30.12 to get your total of 35.84$

7 0
2 years ago
Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

3 0
3 years ago
Divide using polynomial long division<br><br>(3x2 - 11x - 26) = (x - 5)​
julsineya [31]

Answer:

.

Step-by-step explanation:

8 0
3 years ago
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