<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
-7y-4x=17y-2x=53
-4x=24y-2x=53
-2x=24y=53
24y+2x=53
You would have to solve one at a time.
y=53/24
y=2.21
x=53/2
x=26.5
Answer:
1537pounds
Step-by-step explanation:
Given parameters:
Weight of baby at birth = 7.25 pounds
Unknown:
Weight at the end of 8months = ?
Solution:
From the second sentence;
Weight at the end of the eighth month = 212 x weight at birth.
Input the parameters and solve;
Weight at the end of eighth month = 212 x 7.25 = 1537pounds
