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kari74 [83]
2 years ago
5

The width of the rectangle is 1/3 of the length. Find the length and width of the rectangle.

Mathematics
1 answer:
adell [148]2 years ago
6 0

Answer:

1.333333333

Step-by-step explanation:

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Please help solve this!
algol13

Answer:

There’s nothing to solve?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
You are recreating a scale drawing at a different scale. The original scale is 1 cm : 8 m. The new scale is 1 cm : 2 m. In the o
densk [106]

Answer:

The segment should be 36 centimeters long

Step-by-step explanation:

Let us use the ratio method to solve the question

∵ The original scale is 1 cm : 8 m

∵ In the original drawing, the length of a segment is 9 centimeters

→ By using the ratio method

→  cm   :  m

→  1      :  8

→  9     :  x

→ By using the cross multiplication

∵ 1 × x = 9 × 8

∴ x = 72 m

∴ The actual length of the segment is 72 m

∵ The new scale is 1 cm : 2 m

∵ The actual length of the segment is 72 m

→ By using the ratio method

→  cm   :  m

→  1      :  2

→  y      :  72

→ By using the cross multiplication

∵ y × 2 = 1 × 72

∴ 2y = 72

→ Divide both sides by 2 to find y

∴ y = 36

∴ The drawing length of the segment is 36 cm in the new scale

∴ The segment should be 36 centimeters long

6 0
3 years ago
Find the missing value.
denis-greek [22]

Answer:

-7

Step-by-step explanation:

x + 5 = -2

<h2>I hope this helped! :)</h2>
8 0
2 years ago
What is the solution to (x+6)(x+2)=60
Citrus2011 [14]
Distribute to eliminate the parenthesis

x^2 + 2x + 6x + 12 = 60

Combine like terms

x^2 + 8x + 12 = 60

Subtract 60 from both sides

x^2 + 8x - 48 = 0

Factor the equation

(x+12)(x-4)=0
x+12=0
x+4=0

x= -12 and -4
5 0
3 years ago
Give an example of an addition problem in which you would and would not group the addenda differently to add
Ann [662]
Pemdas if you don't know what they are it looks like this.. (4+5)-5+4
similar to that..... 
I am pretty sure you wouldn't add that in a agenda because of the different properties it has but there are plenty more ways i just haven't figured them out 

8 0
2 years ago
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