6x²+x-12
the first thing we need to do is find 2 numbers that add up to equal the middle term (1) but multiply together to get a product of -72 (-12*6)
two numbers that would fit this is 9 and -8
so now we placed 9x and -8x in place of the middle term
6x²+9x-8x-12
now we look for whats common between the first two numbers and divide them out
6x²+9x = 3x(2x+3)
now we do the same with the last two numbers
-8x-12 = -4(2x+3)
notice how the numbers in brackets are the same (2x+3)
we will keep (2x+3) and then combine the numbers on the outside
once we do that you should get an answer of
(3x-4)(2x+3)
hope this helped!
Null: the mean amount of peanut butter in a jar is equal to 32 oz.
alternative: the mean amount of peanut butter in a Jar is less than 32oz.
type 1 error is is rejecting the null when it is actually true. this means that we would say that the mean amount of peanut butter is not equal to 32 when it actually is.
type 2 error is failing to reject the null when it is actually false. this means that we would say the mean amount of peanut butter is equal to 32 when in reality it is less.
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Both are
indicators of the chemical composition of silicate minerals, magmas and rocks.
Mafic is
used for silicate minerals, magmas and rocks that are composed of heavier
elements, like magnesium, iron, calcium and sodium. They are dark and have high
specific gravities.
<span>Opposite to
the this, felsic silicate minerals, magmas and rocks in their composition have
less from these heavy elements. They are composed from silicon, oxygen,
aluminium and potassium, are light in color and have lower specific gravities.</span>
