(a)36 = 6
(b)81 = 9
(c)256 = 16
(d)196 = 14
9514 1404 393
Answer:
(f×g)(2) = 3/4
Step-by-step explanation:
For each of the functions, put 2 where x is and evaluate the expression.
f(2) = (3 -2)/(2² +4) = 1/8
g(2) = 3×2 = 6
Then the product is ...
(f×g)(2) = f(2)×g(2) = (1/8)×6 = 6/8
(f×g)(2) = 3/4
9514 1404 393
Answer:
17. 5
18. 17
Step-by-step explanation:
The distance formula is used for the purpose.
d = √((x2 -x1)² +(y2 -y1)²)
__
17. d = √((3-6)² +(1-5)²) = √((-3)² +(-4)²) = √(9+16) = √25 = 5
The distance between the points is 5 units.
__
18. d = √((-1-7)² +(12-(-3))²) = √(64 +225) = √289 = 17
The distance between the points is 17 units.
Answer:
-3
Step-by-step explanation:
4(2)-2(2+4)+1=8-2(6)+1=9-12=-3
Answer:
Keenan's z-score was of 0.61.
Rachel's z-score was of 0.81.
Step-by-step explanation:
Z-score:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.
This means that 
So



Keenan's z-score was of 0.61.
Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.
This means that
. So



Rachel's z-score was of 0.81.