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3241004551 [841]
3 years ago
10

By which theorem or postulate can the triangles be proven similar?

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0
The answer is D hope it helps
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L. Find the positive square root of each of the following numbers:(a) 36(b) 81(d) 256(c) 196
Yakvenalex [24]
(a)36 = 6
(b)81 = 9
(c)256 = 16
(d)196 = 14
6 0
3 years ago
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Using the functions f(x) = (3 - x)/(x2 + 4) and g(x) = 3x, find the value of (f*g)(2).
wariber [46]

9514 1404 393

Answer:

  (f×g)(2) = 3/4

Step-by-step explanation:

For each of the functions, put 2 where x is and evaluate the expression.

  f(2) = (3 -2)/(2² +4) = 1/8

  g(2) = 3×2 = 6

Then the product is ...

  (f×g)(2) = f(2)×g(2) = (1/8)×6 = 6/8

  (f×g)(2) = 3/4

4 0
3 years ago
Please help me!!! will mark brainliest if you do
Vesnalui [34]

9514 1404 393

Answer:

  17.  5

  18.  17

Step-by-step explanation:

The distance formula is used for the purpose.

  d = √((x2 -x1)² +(y2 -y1)²)

__

17. d = √((3-6)² +(1-5)²) = √((-3)² +(-4)²) = √(9+16) = √25 = 5

The distance between the points is 5 units.

__

18. d = √((-1-7)² +(12-(-3))²) = √(64 +225) = √289 = 17

The distance between the points is 17 units.

4 0
3 years ago
Evaluate and simplify <br> 4a - 2(a + b) + 1 = ? a=2 b=4
o-na [289]

Answer:

-3

Step-by-step explanation:

4(2)-2(2+4)+1=8-2(6)+1=9-12=-3

4 0
3 years ago
Read 2 more answers
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points. Rachel scored 78 p
Artemon [7]

Answer:

Keenan's z-score was of 0.61.

Rachel's z-score was of 0.81.

Step-by-step explanation:

Z-score:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.

This means that X = 80, \mu = 77, \sigma = 4.9

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 77}{4.9}

Z = 0.61

Keenan's z-score was of 0.61.

Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.

This means that X = 78, \mu = 75, \sigma = 3.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{75 - 78}{3.7}

Z = 0.81

Rachel's z-score was of 0.81.

6 0
3 years ago
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