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Ann [662]
3 years ago
11

X² + y² = 36 State the domain and range of the relation

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
6 0

Answer:

X with the power of two is the domain while y with the power of 2 is the range

Step-by-step explanation:

meriva3 years ago
4 0

Answer:

Domain: from -6 to 6, inclusive

Range: from -6 to 6, inclusive

Step-by-step explanation:

It's a circle centred at origin with radius 6

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. upper left chamber is enlarged, the risk of heart problems is increased. The paper "Left Atrial Size Increases with Body Mass
Sonbull [250]

Answer:

Part 1

(a) 0.28434

(b) 0.43441

(c) 29.9 mm

Part 2

(a) 0.97722

Step-by-step explanation:

There are two questions here. We'll break them into two.

Part 1.

This is a normal distribution problem healthy children having the size of their left atrial diameters normally distributed with

Mean = μ = 26.4 mm

Standard deviation = σ = 4.2 mm

a) proportion of healthy children have left atrial diameters less than 24 mm

P(x < 24)

We first normalize/standardize 24 mm

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (24 - 26.4)/4.2 = -0.57

The required probability

P(x < 24) = P(z < -0.57)

We'll use data from the normal probability table for these probabilities

P(x < 24) = P(z < -0.57) = 0.28434

b) proportion of healthy children have left atrial diameters between 25 and 30 mm

P(25 < x < 30)

We first normalize/standardize 25 mm and 30 mm

For 25 mm

z = (x - μ)/σ = (25 - 26.4)/4.2 = -0.33

For 30 mm

z = (x - μ)/σ = (30 - 26.4)/4.2 = 0.86

The required probability

P(25 < x < 30) = P(-0.33 < z < 0.86)

We'll use data from the normal probability table for these probabilities

P(25 < x < 30) = P(-0.33 < z < 0.86)

= P(z < 0.86) - P(z < -0.33)

= 0.80511 - 0.37070 = 0.43441

c) For healthy children, what is the value for which only about 20% have a larger left atrial diameter.

Let the value be x' and its z-score be z'

P(x > x') = P(z > z') = 20% = 0.20

P(z > z') = 1 - P(z ≤ z') = 0.20

P(z ≤ z') = 0.80

Using normal distribution tables

z' = 0.842

z' = (x' - μ)/σ

0.842 = (x' - 26.4)/4.2

x' = 29.9364 = 29.9 mm

Part 2

Population mean = μ = 65 mm

Population Standard deviation = σ = 5 mm

The central limit theory explains that the sampling distribution extracted from this distribution will approximate a normal distribution with

Sample mean = Population mean

¯x = μₓ = μ = 65 mm

Standard deviation of the distribution of sample means = σₓ = (σ/√n)

where n = Sample size = 100

σₓ = (5/√100) = 0.5 mm

So, probability that the sample mean distance ¯x for these 100 will be between 64 and 67 mm = P(64 < x < 67)

We first normalize/standardize 64 mm and 67 mm

For 64 mm

z = (x - μ)/σ = (64 - 65)/0.5 = -2.00

For 67 mm

z = (x - μ)/σ = (67 - 65)/0.5 = 4.00

The required probability

P(64 < x < 67) = P(-2.00 < z < 4.00)

We'll use data from the normal probability table for these probabilities

P(64 < x < 67) = P(-2.00 < z < 4.00)

= P(z < 4.00) - P(z < -2.00)

= 0.99997 - 0.02275 = 0.97722

Hope this Helps!!!

7 0
3 years ago
HELPPPP THIS IS 7TH GRADE MATH AND IM CONFUSEDDDD
irga5000 [103]

Answer:

n-p for the first, p-n for the second

Step-by-step explanation:

6 0
2 years ago
How to solve this question? Please help me
Maurinko [17]

Answer:

≈ 82 feet

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to calculate distance (d)

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

Here the hypotenuse is the distance (d) between the 2 poles, hence

d² = 80² + 45² = 6400 + 2025 = 8425 ( take the square root of both sides )

d = \sqrt{8425} ≈ 82 feet ( to the nearest foot )

8 0
3 years ago
A package of tickets for four home game costs 180$. What proportion can you write to find what 12-game package costs if all indi
Sophie [7]
"21 lol jfhfhdhdhhhhhhh"
6 0
3 years ago
How many solutions can be found for the linear equation? 4(x + 5) - 5 = 8x + 18/ 2
mylen [45]

Answer: The correct option is A.

Explanation:

The given equation is,

4(x+5)-5=\frac{8x+18}{2}

Multiply both sides by 2.

2[4(x+5)-5]=\frac{8x+18}{2}

8(x+5)+2(-5)=8x+18

8x+40-10=8x+18

8x+30=8x+18

Subtract both sides by 8x.

30=18

This statement is false for any value of x, therefore the system of equation have no solution and option A is correct.

6 0
3 years ago
Read 2 more answers
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