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motikmotik
3 years ago
7

Peter bought an antique piece of furniture in 2000 for $10,000. Experts estimate that its value will increase by 12.12% each yea

r. Identify the function that represents its value. Does the function represent growth or decay?
A) V(t) = 10000(1.1212)t; growth
B) V(t) = 10000(0.8788)t; decay
C) V(t) = 10000(1.1212)t; decay
D) V(t) = 10000(0.8788)t; growth
Mathematics
2 answers:
Vladimir [108]3 years ago
5 0
Values increases so we have growth

the exponent will be 1.1212
IrinaK [193]3 years ago
5 0
The answer of it is 1.1212
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1. Curtis was curious about the average height of the different types of plants in his flower and vegetable gardens, so he measu
Nadusha1986 [10]

Answer:

Step-by-step explanation:

hey i got the answer straight from my teach but ony a and c if you have the answer to b let me know  :  ( A) To determine the mean absolute deviation, first calculate the mean. Find the sum of the values: 8 plus 6 plus 9 plus 6 plus 14 plus 9 plus 5 plus 7 equals 64. Then divide the sum by the number of values: 64 divided by 8 equals 8. The mean is 8.

Next, find the distance of each value from the mean :

|8-8|=0 |6-8|=2 |9-8|=1 |6-8|=2 |14-8|=6 |9-8|=1 |5-8|=3 |7-8|=1

0 plus 2 plus 1 plus 2 plus 6 plus 1 plus 3 plus 1 equals 16. Then divide the sum of absolute deviations by the number of data values: 16 divided by 8 equals 2. The MAD of the data is 2.

 

C.  Since the MAD for the vegetable plant data is so much higher than the MAD for the flower data, this indicates that the heights of the vegetable plants vary more than the heights of the flowers    ALSO do you go to k12

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3 years ago
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ArbitrLikvidat [17]
I think its 210 ≤ t
6 0
2 years ago
What is 20/4 - 8 please help
DanielleElmas [232]
To subtract fractions, find the LCD and then combine.

Answer is: -3
6 0
2 years ago
Expressed as a product of its prime factors in index form, a number N is
Elena-2011 [213]

<u>ANSWER</u>



5N^2=3^{2} \times 5^{5} \times x^{6}



<u>EXPLANATION</u>


N=3\times5^2 \times x^3.


5N^2=5(3\times5^2 \times x^3)^2


Recall this property of exponents;


(a^m)^2=a^{m} \times a^m



So our product becomes;


5N^2=5(3\times5^2 \times x^3) \times (3\times5^2 \times x^3)



5N^2=5\times 3\times 3 \times 5^2 \times 5^2 \times x^3 \times x^3


5N^2=3\times 3\times 5 \times 5^2 \times 5^2 \times x^3 \times x^3



Recall this law of exponents:


a^m \times a^n =a ^{m+n}


5N^2=3^{1+1} \times 5^{1+2+2} \times x^{3+3}


5N^2=3^{2} \times 5^{5} \times x^{6}




7 0
3 years ago
Two numbers have these properties both numbers are greater than 6 their highst common factor is 6 there lowest common factor is
levacccp [35]

Answer:

The two numbers are 12 and 30

Step-by-step explanation:

Both numbers are greater than 6

Their HCF is 6 and their LCM is 60.

A possible guess of the two numbers will be 6 and 60, which were given in the question, because they satisfy this HCF and LCM values, but the question also tells us that both numbers are greater than 6.

Now, we will obtain the answer using what we have.

Since the HCF is 6, that means that both numbers that we seek are a multiple of 6.

Next, the LCM is 60. We can divide the LCM by the HCF, that is \frac{60}{6} = 10

This tells us that the two numbers are within 6 and (6 × 10).

Next we write out the factors of the 10 that we got by dividing the LCM by the HCF.

Factors of 10 are: 1, 2, 5 and 10.

We multiply each of this by 6 (which is the HCF, recall that we had said that HCF means that the numbers are a multiple of 6), to get the numbers; <em>6, 12, 30 and 60</em>

Since 6 and 60 are already the given LCM and HCF, the two numbers that we seek are 12 and 30.

4 0
3 years ago
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