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Assoli18 [71]
3 years ago
15

What is the price after taking 25% off $62?​

Mathematics
2 answers:
zlopas [31]3 years ago
8 0

Answer:

<h2>46.5 DOLLARS WILL BE YOUR ANSWER .</h2>

Rama09 [41]3 years ago
6 0

Answer:

$46.50

Step-by-step explanation:

pls mark brainliest

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The total cost after tax to repair Kimber's cracked phone screen is represented by 0.04(30h) + 30h, where h represents the numbe
PSYCHO15rus [73]

In this equation there are few key numbers, thankfully XD, so it does not take too long to figure out that the 0.04 is clearly a tax on the repairs as 30h is representing the hours spent repairing Kimber's phone.

6 0
3 years ago
3⁵.2⁴.2¹.3⁶.(3²)⁴ and down (2³)².3⁶​<br>​
BARSIC [14]

Answer:

\dfrac{3^{13}}{2}

Step-by-step explanation:

Given expression:

\dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot (3^2)^4}{(2^3)^2 \cdot 3^6}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies \dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot 3^8}{2^6 \cdot 3^6}

\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:

\implies \dfrac{3^{(5+6+8)} \cdot 2^{(4+1)}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{2^6 \cdot 3^6}

\implies \dfrac{3^{19} \cdot 2^{5}}{3^6 \cdot 2^6}

\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies 3^{(19-6)} \cdot 2^{(5-6)}

\implies 3^{13} \cdot 2^{-1}

\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:

\implies \dfrac{3^{13}}{2^1}

\textsf{Apply exponent rule} \quad a^1=a:

\implies \dfrac{3^{13}}{2}

4 0
2 years ago
CHECK<br> n =<br> Solve the equation.<br> −4(n − 6)= 12
aksik [14]

- 4(n - 6) = 12 \\ (n - 6) =  \frac{12}{ - 4}  \\ n - 6 =  - 3 \\ n =  - 3 + 6 \\ n = 3

5 0
2 years ago
4. Two families went camping. The Becker family was 4 miles west of the campsite lake. The Dunn family
tresset_1 [31]

They were 1 mile away from each other.

4-3=1 mile

8 0
4 years ago
karen amad an hans have a total of 113 in their wallets? if hans has 4 times the amount of karen an karen has 7 dollars more tha
zvonat [6]

Amount in Han wallet = $ 80

Amount in amad wallet = $ 13

Amount in karen wallet = $ 20

<u>Solution:</u>

Let "h" be the amount in Han's wallet

Let "k" be the amount in karen wallet

Let "a" be the amount in amad wallet

<em><u>They have a total of 113 in their wallet</u></em>

Therefore,

h + k +a = 113 ------- eqn 1

<em><u>If hans has 4 times the amount of karen</u></em>

Amount with Han = 4 times the amount with Karen

h = 4k ------- eqn 2

<em><u>And karen has 7 dollars more than amad</u></em>

k = 7 + a

a = k - 7 ---------- eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

4k + k + k - 7 = 113

6k - 7 = 113

6k = 113 + 7

6k = 120

k = 20

<em><u>Substitute k = 20 in eqn 3</u></em>

a = 20 - 7

a = 13

<em><u>Substitute k = 20 in eqn 2</u></em>

h = 4k = 4(20) = 80

h = 80

<em><u>Summarizing the results:</u></em>

Amount in Han wallet = $ 80

Amount in amad wallet = $ 13

Amount in karen wallet = $ 20

6 0
4 years ago
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