Answer:
Nhan reach town B at 13:24 pm
Step-by-step explanation:
Let
Speed of Nhan=3x km /hour
Speed of Phoung=4x km/hour
After 5 hours,
Distance covered by Nhan=3x(5)=15 xkm
Distance covered by Phuong=4x(5)=20x km
Total distance covered by Nhan to reach town B=15x+102 km
Total distance covered by Phuong to reach town B=20x+52 km
Distance between town A and town B for both person is same therefore,
![15x+102=20x+52](https://tex.z-dn.net/?f=15x%2B102%3D20x%2B52)
![102-52=20x-15x](https://tex.z-dn.net/?f=102-52%3D20x-15x)
![50=5x](https://tex.z-dn.net/?f=50%3D5x)
![x=10](https://tex.z-dn.net/?f=x%3D10)
Speed of Nhan=3(10)=30 km/h
Speed of Phuong=4(10)=40 km/h
Total distance between town A and town B=102+15(10)=252 km
Time taken by Nhan to reach town B from town A=![\frac{distance}{speed}](https://tex.z-dn.net/?f=%5Cfrac%7Bdistance%7D%7Bspeed%7D)
Time taken by Nhan to reach town B from town A=![\frac{252}{30}=8.4 hours](https://tex.z-dn.net/?f=%5Cfrac%7B252%7D%7B30%7D%3D8.4%20hours)
![8.4 hours=8+0.4\times 60](https://tex.z-dn.net/?f=8.4%20hours%3D8%2B0.4%5Ctimes%2060)
=8 hours 24 minutes
1 hour=60 minutes
Nhan reach town B at 13:24 pm