1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lesechka [4]
3 years ago
9

Simplify -12x^4/x^4+8x^5 brainly What is x

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

Answer:

-12+8x^5

bkhlvyuiv,ibk

Ilia_Sergeevich [38]3 years ago
6 0

ANSWER

\frac{ - 12}{1 + 8x}

EXPLANATION

The given rational expression is

\frac{ - 12 {x}^{4} }{ {x}^{4} + 8 {x}^{5}  }

We factor to get;

\frac{ - 12 {x}^{4} }{ {x}^{4} (1+ 8 {x}) }

We can see that:

{x}^{4}

is common to both the numerator and the denominator.

We cancel out the common factors to obtain;

\frac{ - 12 }{ 1+ 8 {x}}

Therefore the simplified form is

\frac{ - 12}{1 + 8x}

You might be interested in
A motorcycle rider travels at an average speed greater than 50 miles per hour.Identify an inequality that can be used to determi
morpeh [17]
50t<375 the process is shown in the following picture

6 0
2 years ago
Using synthetic division, find the quotient Q(x) and the remainder R if the polynomial P(x) = x3 − 2x2 − 5x + 6 is divided by (x
VLD [36.1K]

Answer:

Step-by-step explanation:

1_|   1     -2     -5    6

     <u>          1      -1   -6</u>

       1     -1      -6   0

Q(x)= x^2 - x - 6

R: 0

4 0
2 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
Marina86 [1]

Area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

                                             $=\frac{1}{4} \pi r^2 - \frac{1}{2} bh

                                             $=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times  12 \times 12

                                             $=36\pi -72

                                             $=36(\pi -2) square cm.

Area of the shaded region $=36(\pi -2) square cm

Using Pythagoras theorem,

AC^2=AB^2+BC^2

AC^2=12^2+12^2

AC^2=288

Taking square root on both sides of the equation, we get

AC= 12\sqrt 2 cm

Perimeter of the quadrant of a circle = \frac{1}{4} \times 2\pi r

                                                             $=\frac{1}{4} \times 2 \times \pi \times 12

                                                             $=6 \pi cm

Perimeter of the shaded region = 6 \pi + 12\sqrt 2 cm

                                                    =6 (\pi + 2\sqrt 2) cm

Hence area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

6 0
2 years ago
Can someone help me please.
34kurt

Answer:

c ?

Step-by-step explanation:

7 0
2 years ago
8 y and y are like terms. True or False
ch4aika [34]

Answer:

true

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Other questions:
  • solve y 6.3=0.9y thats all the question i dont understand it so thats why im trying to get the answer to the problem
    15·1 answer
  • 17 is 2.5% of what number?
    5·2 answers
  • Solve the compound inequalities: −7x−10≤60 and x−7&lt;−6
    9·1 answer
  • Write an equation of a line that passes through the point (1,2) and is parallel to the line y=-5x+4
    7·1 answer
  • Find the percent change from 24 to 72. tell whether it is a percent increase or decrease. if necessary, round your answer to the
    14·1 answer
  • What is 5x times (3x^2 -5)
    14·1 answer
  • What is the value of y?<br><br><br><br> 3(y+5)=–2y
    7·1 answer
  • Convert quinary numbers into decimal numbers 340⁵<br>1203⁵<br>2113⁵<br>4444⁵<br>1234⁵​
    11·1 answer
  • Write the equations for a line parallel to the line:
    5·2 answers
  • WILL MARK BRAINLIEST TO THE FIRST PERSON
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!