Answer:
12,288
Step-by-step explanation:
aₙ = 3 (-2)ⁿ⁻¹
a₁₃ = 3 (-2)¹³⁻¹
a₁₃ = 12,288
Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:
Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Answer:
i think ANSWER IS 8
Step-by-step explanation:
48÷8 = 6
Since there is a 70% chance of making $12,000 so have that:
.70 × 12000 = 8400
Also, we have a 10% chance of breaking even, so we also have that:
.10 × 0 = 0
Finally, we have a 20% chance of losing $7400 so we also have that:
.20 × 7400 = 1480
Thus, putting it all together we have:
.70(12000) + .10(0) + .20(7400) = 8400 + 0 + 1480 = 9880
Therefore, the expected value is:
$9880
Let's start with option A --> $23 per hour x 40 hours = 23 x 40 = 920 = $920
That means we have to find how many $ x 5% = $920
We'll call our unknown amount: "B", so B x 0.05 = $920
To find B you have to get ride of everything on its side:
(B x 0.05) / 0.05 = 920 / 0.05 ----> we have to do the same operations on each side.
Now we have B = 920 / 0.05 ----> B = $18,400
The salesperson must sell $18,400 in order to earn the same amount as the first option.
