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Aleks04 [339]
3 years ago
6

Solve the equation and justify each step by stating the algebraic property use or what was done for each step.

Mathematics
1 answer:
Levart [38]3 years ago
3 0
5(3-x) + 3x = 6x -1

15-5x+3x = 6x-1

15-2x = 6x-1

2=x
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How many cubic feet of water can the following in ground swimming pool hold
guapka [62]

Answer:

do length times width times height and see what you get if your answer is not on there split the figure into 2 shapes and do l*w*h to both and add you 2 figures together then see if you have your answer.

Step-by-step explanation:

do length times width times height and see what you get if your answer is not on there split the figure into 2 shapes and do l*w*h to both and add you 2 figures together then see if you have your answer. hope that helps!

3 0
2 years ago
Which set of ordered pairs represents a function?
Mrac [35]
The second one because for every x value there is one and only one y value. If you plotted the points and graphed it, you would know it is not a function if it doesn't pass the vertical line test. Notice the same x values show up repeatedly in the other ordered pairs with different y values. Only one y value for every x value
5 0
2 years ago
What is 6,051 x 10^5 written in standard form?
Setler79 [48]

Answer:

605100

Step-by-step explanation:

6.051*10^5=605100

6 0
2 years ago
Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint
Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x)  =  1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0
3 years ago
Helpppp. I don’t understand
Pie
Multiply 2^(-5) by 2^6.  The correct result is 2^1, or just 2 (inches).
7 0
3 years ago
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