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krek1111 [17]
3 years ago
8

Find the difference between (3x+7)and (4x+2)

Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

-x+5

Step-by-step explanation:

(3x+7)-(4x+2)

=3x-4x+7-2

=-x+7-2

=-x+5

Answer: -x+5

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12<br> The value of x must be greater than<br><br> a .0<br> B.1<br> C.3<br> D.7
Likurg_2 [28]

Answer:

must be greater than 7

Step-by-step explanation:

using pythagoras theorem

a^2=b^2-c^2

x^2=15^2-12^2

x^2=225-144

x^2=81

take square root both sides

√x^2=√81

x=9

and 9 is greater than 7

7 0
3 years ago
Which system of equations below has infinitely many solutions? y = –3x 4 and y = –3x – 4 y = –3x 4 and 3y = –9x 12 y = –3x 4 and
Flura [38]

the equations y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions. option B is correct.

<h3>What is the linear system?</h3>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Condition for the parallel lines.

L1,  ax + bx + c = 0

L2, dx + ey + f = 0

If \rm \dfrac{a}{d} = \dfrac{b}{e} = \dfrac{c}{f} then lines have infinitely many solutions.

<h3>Which system of equations below has infinitely many solutions?</h3>

y = –3x + 4 and 3y = –9x + 12

On comparing we have

a = -3 , b = 1, and c = 4

d = -9 , e = 3, and f = 12

Then their ratio will be

\rm \dfrac{1}{3} = \dfrac{-3}{-9} = \dfrac{4}{12}\\\\\rm \dfrac{1}{3} = \dfrac{1}{3} = \dfrac{1}{3}

Hence  y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions.

Thus the option B is correct.

More about the linear system link is given below.

brainly.com/question/20379472

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Step-by-step explanation:

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