\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Answer:
-7/10
Explanation:
Given the expression
We can rewrite the expression as:
The number line showing the location of the two numbers is attached below. Therefore:
The cost of aquiring the source is high, i believe
Answer:
<em>4</em>
Step-by-step explanation:
The solid triangle dilated to become the dashed triangle.
Compare two corresponding sides. For example, the vertical side of the solid triangle measures 3 units. The vertical side of the dashed triangle measures 12 units. 12/3 = 4. The dilation is 4. The scale factor is 4.
Answer:
And solving we got:
We can find the sings of the second derivate on the following intervals:
Concave up
inflection point
Concave down
inflection point
Concave up
Step-by-step explanation:
For this case we have the following function:
We can find the first derivate and we got:
In order to find the concavity we can find the second derivate and we got:
We can set up this derivate equal to 0 and we got:
And solving we got:
We can find the sings of the second derivate on the following intervals:
Concave up
inflection point
Concave down
inflection point
Concave up
