Answer:
Step-by-step explanation:
Let the base camp is point A and boats' locations after two hours are points B and C.
By connecting the three points together we get a triangle ABC with sides:
- AB = 50*2 = 100 km
- AC = 70*2 = 140 km
The angle between AB and AC is:
- 60 + 50 = 110 degrees (opposite directions from south)
We are looking for the distance BC, which can be found by using the law of cosines:
- BC² = AB² + AC² - 2AB*AC*cos ∠BAC
- BC² = 100² + 140² - 2*100*140*cos 110°
- BC² = 39176.56 (rounded)
- BC = √39176.56 = 197.93 km (rounded)
The distance between the boats is 197.93 km.
-1+3m=2m+4
put the like terms together
3m-2m=4+1
m=5
Answer: The p(success) = 0.6
Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.
If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.
That is 0.48 + 0.16 = 0.64
Rounding our answer to one decimal place gives us 0.6.
4/5(v - 7) = 2...distribute the 4/5 thru the parenthesis
4/5v - 28/5 = 2 ...multiply everything by 5
4v - 28 = 10...add 28 to both sides
4v = 10 + 28
4v = 38
v = 38/4 reduces to 19/2 or 9 1/2 <==
