Answer:
There are 8 tens and 2 ones
Step-by-step explanation:
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1/5, 3/4, 83/100.
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Answer:
x = ±sqrt(y-11)
Step-by-step explanation:
y = x^2 +11
Subtract 11 from each side
y -11 = x^2 +11-11
y-11 = x^2
Take the square root of each side
±sqrt(y-11) = sqrt(x^2)
±sqrt(y-11) = x
Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
