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myrzilka [38]
3 years ago
11

Solve for x if 10/4x-3 = 2​

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

Kindly see attached picture

hope it helped you:)

Marysya12 [62]3 years ago
3 0

Answer:

We need to solve this equation:

\frac{10}{4x}-3=2

We pass -3 to the right summing:

\frac{10}{4x} = 2 + 3

\frac{10}{4x}=5

We pass the 4x that is dividing to the right multiplying:

10 = 5*4x

10=20x

We pass the 20 of the right to the left dividing:

\frac{10}{20}=x

x=\frac{1}{2}

Now, we know x=\frac{1}{2}, so we can verify:

\frac{10}{4*\frac{1}{2}}-3 = 2

\frac{10}{2}-3=2

5 - 3 = 2 TRUE

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1/2 times ? Equals 3 1/2
stepan [7]

Answer:

7

Step-by-step explanation:

1/2(x)=7/2

divide both sides by 1/2

x=\frac{7}{2}÷\frac{1}{2}

x=\frac{7}{2}·\frac{2}{1}

x=14/2=7

4 0
3 years ago
Write an inequality for each situation.
pickupchik [31]

Answer:

A. 56-6m<20

B. 2.95b+28<450

13. Less than, greater than, going over or not going over.

Step-by-step explanation:

A. The answer to the first question can be simple. If she can scan 6 photographs per minute, then we would write the inequality 56-6m<20, since we are subtracting 6 from 56 every minute, we would write 6 per minute as 6m, and subtract that from 56. Lastly, since it says <u>less than</u>, we need to put the less than symbol, the mouth facing towards the 20 as the greater number.

B.  If she has spent 28, that means that we put -28 on the equation as a constant. Then, we put the price times the number of batteries she bought, or 2.95b, and put a less than symbol, since we want to spend less than the 450 gift card. So the equation would be 2.95b+28<450

13. Key words to indicate inequalities can be less than, greater than, without going over, going over.

Hope this helps! :D

5 0
4 years ago
Using the pleading the square method find the vertex of the function f(x)=5x^2+10x+8
Inga [223]

credits to the owner:lisboa, another brainly expert

5 0
4 years ago
A tank contains 60 kg of salt and 1000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain
MissTica

Answer:

(a) 60 kg; (b) 21.6 kg; (c) 0 kg/L

Step-by-step explanation:

(a) Initial amount of salt in tank

The tank initially contains 60 kg of salt.

(b) Amount of salt after 4.5 h

\text{Let A = mass of salt after t min}\\\text{and }r_{i} = \text{rate of salt coming into tank}\\\text{and }r_{0} =\text{rate of salt going out of tank}

(i) Set up an expression for the rate of change of salt concentration.

\dfrac{\text{d}A}{\text{d}t} = r_{i} - r_{o}\\\\\text{The fresh water is entering with no salt, so}\\ r_{i} = 0\\r_{o} = \dfrac{\text{3 L}}{\text{1 min}} \times \dfrac {A\text{ kg}}{\text{1000 L}} =\dfrac{3A}{1000}\text{ kg/min}\\\\\dfrac{\text{d}A}{\text{d}t} = -0.003A \text{ kg/min}

(ii) Integrate the expression

\dfrac{\text{d}A}{\text{d}t} = -0.003A\\\\\dfrac{\text{d}A}{A} = -0.003\text{d}t\\\\\int \dfrac{\text{d}A}{A} = -\int 0.003\text{d}t\\\\\ln A = -0.003t + C

(iii) Find the constant of integration

\ln A = -0.003t + C\\\text{At t = 0, A = 60 kg/1000 L = 0.060 kg/L} \\\ln (0.060) = -0.003\times0 + C\\C = \ln(0.060)

(iv) Solve for A as a function of time.

\text{The integrated rate expression is}\\\ln A = -0.003t +  \ln(0.060)\\\text{Solve for } A\\A = 0.060e^{-0.003t}

(v) Calculate the amount of salt after 4.5 h

a. Convert hours to minutes

\text{Time} = \text{4.5 h} \times \dfrac{\text{60 min}}{\text{1h}} = \text{270 min}

b.Calculate the concentration

A = 0.060e^{-0.003t} = 0.060e^{-0.003\times270} = 0.060e^{-0.81} = 0.060 \times 0.445 = \text{0.0267 kg/L}

c. Calculate the volume

The tank has been filling at 6 L/min and draining at 3 L/min, so it is filling at a net rate of 3 L/min.

The volume added in 4.5 h is  

\text{Volume added} = \text{270 min} \times \dfrac{\text{3 L}}{\text{1 min}} = \text{810 L}

Total volume in tank = 1000 L + 810 L = 1810 L

d. Calculate the mass of salt in the tank

\text{Mass of salt in tank } = \text{1810 L} \times \dfrac{\text{0.0267 kg}}{\text{1 L}} = \textbf{21.6 kg}

(c) Concentration at infinite time

\text{As t $\longrightarrow \, -\infty,\, e^{-\infty} \longrightarrow \, 0$, so A $\longrightarrow \, 0$.}

This makes sense, because the salt is continuously being flushed out by the fresh water coming in.

The graph below shows how the concentration of salt varies with time.

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3 years ago
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6sqrt2 for both since there equivalent
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