Answer:

Step-by-step explanation:
The limit is:

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

by replacing, and applying repeatedly you obtain:

hence, the limit of the function is -1/14
Is their any multiple questions
Well $25 is the standard price initially.
$10 is added every hour as a constant rate.
Therefore a. 25 + 10h is the right expression
Answer:
Hey it’s 283
Step-by-step explanation: