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aalyn [17]
3 years ago
10

A book vendor is trying to sell his booking collection. One customer buys 1/4 of his books , another buys 1/3 of his books ,and

a third buys 1/6 of his books. If the vendor is left with 15 books , how many did he start out with ?
Mathematics
2 answers:
Anna11 [10]3 years ago
7 0

Answer:

365535


Step-by-step explanation:

365535

Ivahew [28]3 years ago
6 0

Answer: 60 books

Step-by-step explanation:

One customer buys 1/4 of a book vendor's books , another buys 1/3 of his books ,and the third person buys 1/6 of his books.

The lowest common multiple of 4, 3 and 6 is 12

1/4 × 12 = 3

1/3 × 12 = 4

1/6 × 12 = 2

We add all together= 3+4+2= 9

So we've gotten our numerators as 9 and denominator as 12 which is 9/12 = 3/4

Since the total books bought is 3/4. The fraction of books left will be

1-3/4 = 1/4

The book vendor has 15 books left. So we divide 15 by 1/4.

= 15 ÷ 1/4

= 15 × 4

= 60

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3 years ago
Read 2 more answers
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
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<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

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The third box contained two more pounds than the first box i.e.

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Therefore , Sum of pounds of candy are :

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