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alina1380 [7]
3 years ago
11

Find three consecutive integers whose sum is -57

Mathematics
2 answers:
jekas [21]3 years ago
5 0
<span>x, x+1,x+2
...
x+x+1+x+2=-147
3x+3=-147
-3 -3
3x=-147-3

3x=-150
/3
x= -150/3
x= -50
..
-50,-49,-48
... i think that is it 8)

</span>
kakasveta [241]3 years ago
3 0

Answer:

Step-by-step explanation: Don't be thrown off by the negative in this problem. Integers can be negative so it's not problem to be told that the sum of our 3 consecutive integers is -57.

Use X, X + 1, and X + 2 to represent the integers.

The rest of my work is attached in the image provided.

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Answer:

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Step-by-step explanation:

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9x^2 + 18x + 9y^2 + 9y = 36

Factor out the coefficient 9:

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Complete the square of x^2 + 2x and then do the same for y^2 + 2y:

x^2 + 2x + 1 - 1 + y^2 + 2y + 1 - 1 = 4

Rewrite x^2 + 2x + 1 as the square of the binomial x + 1:

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Collect the constant terms on the right side:

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Rewrite 6 as (√6)^2:

(x + 1)² + (y + 1)² = (√6)² is the equation in standard form (x - h)² + (y - k)² = r²

Completing the square is done as follows:  x^2 + 2x

Start with x^2 + 2x

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2.  Square this result and add it to, and subtract it from x^2 + 2x

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3.  Rewrite the first three terms as the square of a binomial:  

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Do the same for y² + 2y.

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