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melomori [17]
3 years ago
12

Line CD contains points C(7, 4) and D(6, 1). Line JK is parallel to line CD. Which two points lie on line JK?

Mathematics
2 answers:
Andru [333]3 years ago
6 0
From 6,1 to 7,4 
We can determine the slope of the line
rise/run
3/1=3

Now we know the slope of the line, a line parallel to it must obtain the same slope, therefore, I tried to see if the increase in y is three times the increase in x
I found the true pair to be A

(-4,1) and (-2,7)

Paha777 [63]3 years ago
4 0
Line Jk is parallel to  CD  so their slopes  must be the same.

Slope of CD = (4-1)/(7-6) = 3/1 = 3
Try Option A 
Slope of JK = 7(-1)/(-2 - -4) = 6 / 2  = 3

So the points are  in Choice A
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3 0
3 years ago
What is the slope of a line that passes through the points (-5,-3) and (9,-6)
kipiarov [429]
To find the slope given two points, you need to subtract the two y values over the two x values
(-5,-3)  (9,-6)
-5 will be x1, and -3 will be y1. 9 will be x2, and -6 will be y2. You then need to put the numbers in the correct place in the equation.
y2-y1      -6-(-3)     -9
-------- =   -------- =  ----
x2-x1       9-(-5)     14
Now that we have the slope (-9/14) you can use one of the coordinates to find the value of b.
Let's use (9,-6).
-6=-9/14(9)+b
-6=-81/14+b
+81/14
b=-3/14
Your final equation is y=-9/15x-3/14


7 0
3 years ago
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