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melomori [17]
3 years ago
12

Line CD contains points C(7, 4) and D(6, 1). Line JK is parallel to line CD. Which two points lie on line JK?

Mathematics
2 answers:
Andru [333]3 years ago
6 0
From 6,1 to 7,4 
We can determine the slope of the line
rise/run
3/1=3

Now we know the slope of the line, a line parallel to it must obtain the same slope, therefore, I tried to see if the increase in y is three times the increase in x
I found the true pair to be A

(-4,1) and (-2,7)

Paha777 [63]3 years ago
4 0
Line Jk is parallel to  CD  so their slopes  must be the same.

Slope of CD = (4-1)/(7-6) = 3/1 = 3
Try Option A 
Slope of JK = 7(-1)/(-2 - -4) = 6 / 2  = 3

So the points are  in Choice A
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Find the determinant of the matrix.
Jobisdone [24]

Answer:

-276

Step-by-step explanation:

We'll use the method of cofactors.  Use the coefficient +6 for

9   2

8   10

This gives you one third of the solution:  6 {(9)·(10) - (8)(2) },  or 444.

Next, use the coefficient 9, taking care to change the sign to -9  as follows:

     9   1

-9 |           |     =   -9(90 - 8) = -9(82) = -738  

      8  10

Finally with +2 as y our coefficient, evaluate the cofactor

9  1

9  2

ending up with  

+2(18-9) = +2(9) = 18

Finally add these three results together:

+444 - 738 + 18  =  -276

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3 years ago
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Annette [7]

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taurus [48]
Y=m(x-x1)+y1
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Answer:

6

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borishaifa [10]
The answer is c




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