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lapo4ka [179]
3 years ago
11

In 63, in which place is the 3? ones tens

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0
The digit 3 is in the ones place
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If 32^2c= 8^c+7, what is the value of c
Leona [35]

\bf 32^{2c}=8^{c+7}~~ \begin{cases} 32=2\cdot 2\cdot 2\cdot 2\cdot 2\\ \qquad 2^5\\ 8=2\cdot 2\cdot 2\\ \qquad 2^3 \end{cases}\implies (2^5)^{2c}=(2^3)^{c+7} \\\\\\ 2^{5(2c)}=2^{3(c+7)}\implies \stackrel{\textit{if the bases are the same, then so are the exponents}}{5(2c)=3(c+7)\implies 10c=3c+21} \\\\\\ 7c=21\implies c=\cfrac{21}{7}\implies c=3

3 0
3 years ago
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Teddy is writing a proof about the figure shown on the coordinate plane below. He wants to show that quadrilateral WXYZ is a par
faltersainse [42]
B is the answer show that segments WX AND YZ have equal lengths
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3 years ago
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Solve the system -10=-2y+x 6y=3x+11
belka [17]

Answer: No Solutions exist

Step-by-step explanation:

We have the following system of equations

-10=-2y+x

6y=3x+11

Rewriting the second equation we have:

-11=-6y+3x

Now we multiply the first equation by -3 and add it to the second equation

30=6y-3x

-11=-6y+3x

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19=0

Equality is not satisfied. Then the system has no solution

5 0
3 years ago
\root(3)(-3)\root(3)(-5)=\root(3)(15) true or false
Oksi-84 [34.3K]

The equation \sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15} is true

<h3>How to determine the true statement?</h3>

The equation is given as

\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}

Apply the law of indices

\sqrt[3]{-3 * -5} = \sqrt[3]{15}

Evaluate the product

\sqrt[3]{15} = \sqrt[3]{15}

Both sides of the equation are the same

Hence, the equation \sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15} is true

Read more about equations at:

brainly.com/question/2972832

#SPJ1

3 0
2 years ago
Solve for x round to the nearest degree if necessary
natulia [17]

Answer: 35.9 degrees

Step-by-step explanation:

Since cosine(x) is adjacent/hypotenuse, cosine(x) = 47/58.

Therefore we can take the arc cosine of 47/58, and we get x is about 35.9

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3 years ago
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