Find the length of the following tangent segments to the circles centered at O and O's whose radii are 5 and 3 respectively and
the distance between O and O's is 12. I will post diagram.
1.) The tangent segment AB
1.) The tangent segment AB
1 answer:
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Answer:
a. 8.4 km b. 20 km/hr or 20,000 m/hr
Step-by-step explanation:
This is your polynomial:
The important thing to realize is that d(v) is the distance it takes for the boat to stop. That will come later, in part b. Besides that, we also need to remember that v is velocity, which is speed, in km/hr.
For part a. we are looking for d(v), the stopping distance, when v = 10. That means that we will sub in a 10 for each v in the function and solve for d(v):
so
d(10) = 8.4 km
Now comes the part I was referring to above. Part b is asking us the speed of the boat if it takes 11.6 meters to stop. If d(v) is the stopping distance, we sub 11.6 in for d(v) in the function:
The only way w can solve this for velocity is to get everything on one side of the equals sign, set the polynomial equal to 0, then plug the values into the quadratic formula.
Plugging that into the quadratic formula gives you 2 values of velocity:
v = 20 km/hr and -70 km/hr
We all know that neither time nor distance in math will EVER be negative so we can discount the negative number. However, I believe that you asked for the distance in meters, so 20 km/hr is the same as 20,000 m/hr.