Answer:
In option a, w < 10
in option b, w = 10 and 2(20) + 2(10) = 40 + 20 = 60 < 150
in option c, w > 10 but 2(60) + 2(20) = 120 + 40 = 160 > 150
In option d, w > 10 but 2(55) + 2(30) = 110 + 60 = 170 > 150
Therefore the corect answer is option b.
Step-by-step explanation:
You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Answer:
it means that there will be no solution .
<h2>
<em>hope this helped <3</em></h2><h2>
<em /></h2>
<em>-bubb0</em>
Answer: c. 29.65 + 0.90r ≤ 41
Repari cost (x) = y = 35.25 x + 40
x = number of hours to repair the car.
Every hour the cost will increase 35.25, becasue 40 is a fixed cost.
if x = 1, repair cost(1) = 35.25 + 40
if x = 2, repair cost (2) = 35.25*2 + 40
if you subtract repair cost (1) from repair cost (2) you get 35.25*2 - 35.25 = 35.25
The same thing every time the repair time increases one hour.
Answer: the last option of the list, for every hour of labor, the cost increases by $35.25
